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23 Mar 2020, 04:59
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:10) correct
26%
(01:52)
wrong
based on 269
sessions
History
Date
Time
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Not Attempted Yet
A display case contains a certain number of donuts, some chocolate, some jelly filled, and the rest plain. One-sixth of the donuts are chocolate. How many chocolate donuts must be added so that one-fourth of the total donuts are chocolate?
(1) There are 40 plain donuts in the case.
(2) The ratio of plain donuts to jelly-filled donuts is 2:1.
(1) There are 40 plain donuts in the case.
(2) The ratio of plain donuts to jelly-filled donuts is 2:1.
Archit3110
Major Poster
23 Mar 2020, 11:45
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Bunuel
let total donuts = x
so x/6 = chocolate and 5x/6 are jelly filled and plain
#1
40 are plain donuts
insufficient
#2
plain / jelly filled = 2/1
or say plain 2/3 * x = total plain insufficient
from 1 &2
40 *3*1/2 = x ; 60
total donuts = 60
so chocolate are 10
sufficient to determine the value of additional chocolate donuts required to be added
IMO C
rizzatoandrea
Joined: 11 Mar 2020
Last visit: 07 Apr 2020
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Location: Italy
Concentration: General Management, International Business
Schools: Bocconi '21 (S) Imperial '22 HEC '22
GPA: 4
WE:Project Management (Manufacturing)
27 Mar 2020, 03:30
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Archit3110
That's right, thank you for the mathematical explanation.
As you explained above, both sentences are inconsistent if considered alone, and only their "aggregation" could generate a situation in which we have all details to extract the final answer.
So, also in my perspective, the right choice is C
