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15 Apr 2020, 04:06
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
58% (01:39) correct
42%
(01:26)
wrong
based on 233
sessions
History
Date
Time
Result
Not Attempted Yet
15 Apr 2020, 04:23
Kudos
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Bunuel
Solution
Step 1: Analyse Question Stem
Is yz > wz?
Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: \(y > w\)
- • Case I: If z is positive, then \(y*z > w*z\).
• Case II: If z is negative, then \(y*z < w*z\)
• We are getting different results.
Statement 2: \(z^3 < z\)
- • We don’t know anything about y and w
- o Thus, we can’t answer the question.
Step 3: Analyse Statements by combining.
From statement 1: \(y > w\)
Statement 2: \(z^3 < z\)
- • Case I: If \(z = \frac{1}{ 2}\), then \(z^3 = \frac{1}{ 8}, z^3 < z\)
- o Then \(\frac{y}{2} > \frac{w}{2}, y*z > w*z\)
- o Then \(y*-2 < w*-2, y*z < w*z\)
15 Apr 2020, 04:29
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Is \(yz > wz\) ?
--> \(z (y -w) >0\) ???
(Statement1): \(y >w\)
--> \(y -w >0\)
No info about what z is.
Insufficient
(Statement2): \(z^{3} <z\)
--> \(z( z-1)(z +1) <0\)
\(z < -1\) and \(0< z<1.\)
No info about what \((y-w)\) is.
Insufficient
Taken together 1&2,
if \(z <-1\) and \(y-w >0\), then \(z (y -w)\) is less than zero (NO)
if \(0< z<1\) and \(y-w >0\), then \(z (y -w)\) is greater than zero (YES)
Insufficient
Answer (E).
--> \(z (y -w) >0\) ???
(Statement1): \(y >w\)
--> \(y -w >0\)
No info about what z is.
Insufficient
(Statement2): \(z^{3} <z\)
--> \(z( z-1)(z +1) <0\)
\(z < -1\) and \(0< z<1.\)
No info about what \((y-w)\) is.
Insufficient
Taken together 1&2,
if \(z <-1\) and \(y-w >0\), then \(z (y -w)\) is less than zero (NO)
if \(0< z<1\) and \(y-w >0\), then \(z (y -w)\) is greater than zero (YES)
Insufficient
Answer (E).
