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The question can be reduced to finding ten's digit of (ab)^2. 1) a=5k where k is some positive integer. This alone will not be sufficient to tell us ten's digit. 2) b=2x where x is some posiitive integer. This alone as well, is not sufficient to tell us about the ten's digit.
Taking 1 and 2 together, we know that product is (10kx)^2. Since 100*any integer will give ten's digit as 0, we can mark the answer as C.
The question says that a and b are positive integers. This means that both ab and ba are two-digit numbers with non-zero digits. We are to find the tens digit of the product of ab and ba.
From statement I alone, a is divisible by 5. This means that a=5. If a=5 and b=1, ab=51 and ba = 15. The product of ab and ba ends with 65. The tens digit is 6. If a=5 and b=2, ab=52 and ba=25. The product of ab and ba ends with 00. The tens digit is 0. Statement I alone is insufficient to find a unique value for the tens digit. Answer options A and D can be eliminated. Possible answer options are B, C or E.
From statement II alone, b is divisible by 2. This means that b = 2 or 4 or 6 or 8. This is insufficient to find the tens digit of the product of ab and ba since we do not know the value of a. Answer option B can be eliminated. Possible answer options are C or E.
Combining statements I and II, we have the following: From statement I, a=5 and from statement II, b = 2 or 4 or 6 or 8.
Therefore, possible values for ab = 52 or 54 or 56 or 58 AND Possible values for ba = 25 or 45 or 65 or 85.
There can be more than one value for the tens digit of the product. The combination of statement is insufficient. Answer option C can be eliminated.
The correct answer option is E.
Kritisood, I think you may have to change the OA to E. Please confirm.
The question says that a and b are positive integers. This means that both ab and ba are two-digit numbers with non-zero digits. We are to find the tens digit of the product of ab and ba.
From statement I alone, a is divisible by 5. This means that a=5. If a=5 and b=1, ab=51 and ba = 15. The product of ab and ba ends with 65. The tens digit is 6. If a=5 and b=2, ab=52 and ba=25. The product of ab and ba ends with 00. The tens digit is 0. Statement I alone is insufficient to find a unique value for the tens digit. Answer options A and D can be eliminated. Possible answer options are B, C or E.
From statement II alone, b is divisible by 2. This means that b = 2 or 4 or 6 or 8. This is insufficient to find the tens digit of the product of ab and ba since we do not know the value of a. Answer option B can be eliminated. Possible answer options are C or E.
Combining statements I and II, we have the following: From statement I, a=5 and from statement II, b = 2 or 4 or 6 or 8.
Therefore, possible values for ab = 52 or 54 or 56 or 58 AND Possible values for ba = 25 or 45 or 65 or 85.
There can be more than one value for the tens digit of the product. The combination of statement is insufficient. Answer option C can be eliminated.
The correct answer option is E.
Kritisood, I think you may have to change the OA to E. Please confirm.
Hope that helps!
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Hi, I had marked E as well but the OA was C hence had posted to see where I was going wrong. I guess I was correct in thinking, thanks!
The question can be reduced to finding ten's digit of (ab)^2. 1) a=5k where k is some positive integer. This alone will not be sufficient to tell us ten's digit. 2) b=2x where x is some posiitive integer. This alone as well, is not sufficient to tell us about the ten's digit.
Taking 1 and 2 together, we know that product is (10kx)^2. Since 100*any integer will give ten's digit as 0, we can mark the answer as C.
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Hello jpan, If we assume ab = 37, ba = 73. In this case, it’s wrong to assume that ab*ba = \((ab)^2\). Clearly, 37 * 73 is not equal to \((37)^2\). In general, it’s not advisable to assume that ab * ba = \((ab)^2\).
Additionally, a and b represent the digits of a number and hence have to be single digits. So, k cannot be any positive integer, it HAS to be 1. Similarly, x cannot be any positive integer, it HAS to be 1 or 2 or 3 or 4.
This question asks us to find the tens digit of the product of ab and ba and hence the combination of statements is not sufficient.
The question can be reduced to finding ten's digit of (ab)^2. 1) a=5k where k is some positive integer. This alone will not be sufficient to tell us ten's digit. 2) b=2x where x is some posiitive integer. This alone as well, is not sufficient to tell us about the ten's digit.
Taking 1 and 2 together, we know that product is (10kx)^2. Since 100*any integer will give ten's digit as 0, we can mark the answer as C.
Hello jpan, If we assume ab = 37, ba = 73. In this case, it’s wrong to assume that ab*ba = \((ab)^2\). Clearly, 37 * 73 is not equal to \((37)^2\). In general, it’s not advisable to assume that ab * ba = \((ab)^2\).
Additionally, a and b represent the digits of a number and hence have to be single digits. So, k cannot be any positive integer, it HAS to be 1. Similarly, x cannot be any positive integer, it HAS to be 1 or 2 or 3 or 4.
This question asks us to find the tens digit of the product of ab and ba and hence the combination of statements is not sufficient.
Hope that helps!
Show more
Hi Aravind, I would agree with you but I the question seems ambiguous to me. Nowhere is it given that a and b are 1 digit numbers and I did not automatically assume that ab meant a number formed by appending b to a. I assumed ab was product of a and b where they can be any integers and thus reduced the question to (ab)^2. I would never assume number * reverse of the number = number square ! Thanks for your solution though
The question did not mention anything about a and b representing digits to a 2-digit number (even though these letters are conventionally used to illustrate that), and I think in the GMAT the question would explicitly state so. Hence, I do not think it is appropriate to assume.
I have treated a and b as independent integers and can potentially be 1, 2 or even 3-digit integers. We do not know this fact. However, we can start off by expressing ab * ba as a^2b^2
Statement (1): a is divisible by 5. a = 5 * integer a^2 = 5^2 * integer^2 Therefore, we can conclude that a is a multiple of 25 (amongst other factors, which we do not know). a^2 = 25, 50, 75, 100, ... Since we do not have information on what b is, this alone is insufficient.
Statement (2): b is divisible by 2. b = 2 * integer b^2 = 2^2 * integer^2 Therefore, we can conclude that b is a multiple of 4 (amongst other factors, which we do not know). b^2 = 4, 8, 12, 16, ... Since we do not have information on what a is, this alone is insufficient.
(1)+(2): a^2b^2 = 5^2 * 2^2 * integer = 25 * 4 * integer = 100 * integer. Hence, the tens-digit will always be 0 since a^2b^2 is a multiple of 100. Hence, sufficient. Answer C.
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