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Explanation:

Statement 1: 2/x < 1
2/x - 1 < 0
2-x/x < 0
x-2/x > 0
x>2 or x<0
Not Sufficient

Statement 2: 4/x > x
4/x - x > 0
(4-x^2)/x > 0
(x^2-4)/x < 0
(x-2)(x+2)/x < 0
0<x<2 ; x<-2
So, x<2
Sufficient

IMO-B
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ajaygaur319
Is x > 2?

(1) 2/x < 1
(2) 4/x > x

this question tests the basic concept on inequalities:
you cannot multiply both sides by an unknown unless you know the sign of it (x in this case)

st 1:
\(\frac{2}{x}-1<0\)
\(\frac{(2-x)}{x}<0\)
taking neg sign out of the expression as to plot on wavy line the expression needs to be of the form (x-a)
\(\frac{(x-2)}{x}>0\)
plot this on the wavy line you get
x>2 OR x<0 two answers hence NS

st 2:
\(\frac{4}{x}>x\)
\(\frac{4}{x}-x>0\)
\(\frac{(4-x)^2}{x}>0\)
\(\frac{(2+x)(2-x)}{x}>0\)
taking -ve out of (2-x) expression as to plot on wavy line the expression needs to be of the form (x-a)
\(\frac{(x+2)(x-2)}{x}<0\) (sign changes as we are multiplying by neg on both sides)
plot on the wavy line
x<-2 OR 0<x<2 both cases it gives us a def no. Hence sufficient.
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ajaygaur319
Is x > 2?

(1) 2/x < 1
(2) 4/x > x

It is better to mention in the question that \(x\neq{0}\)

(1) \(\frac{2}{x} < 1\)
If x<0, \(\frac{2}{x}<0 < 1\)...so answer to 'Is x>2?' will be NO.
If x>0,\(\frac{2}{x} < 1\)=>\(2<x\)...so answer to 'Is x>2?' will be YES.
Insufficient

(2) 4/x > x
\(\frac{4}{x} - x>0\)
\(\frac{4-x^2}{x}>0\)
If x>0, \(4-x^2>0....x^2<4\), that is x<2...answer is NO
If x<0...answer will again be NO.
Sufficient

B
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