Rick is in a room with 4 other people. If the other people weigh 100,

Question

Rick is in a room with 4 other people. If the other people weigh 100, 120, 135 and 155 pounds, does Rick weigh 110 pounds?

(1) The weight of the third heaviest person is equal to the average (arithmetic mean) of the five person's weight.
(2) Rick is not the heaviest or lightest person in the room.

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urshi · Answer

This is a Yes/No type of question

Question is if Rick's weight = 110 or not.

Statement 1 :

Let's assume Rick's weight is 110.

Then 120 should be weight of the 3rd heaviest person. But this is not the average of 5 person's weight. So this implies Rick's weight is not equal to 110.

We can definitely answer NO.

Sufficient

Statement 2 :

Rick's weight can be 110 or 105 or 130.

So insufficient

Answer : Option A

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yashikaaggarwal · Answer

(1) The weight of the third heaviest person is equal to the average (arithmetic mean) of the five person's weight.
3rd heaviest weight = median
Median = mean
Rick weight = X
100, 120, 135, 155 and X
100+120+135+155+X/5 
510+X = 5 median
Let say Rick weight = 110 
510+110 = 5*120 (median)
620≠600
So Rick weight is never equal to 110.
(Sufficient)

(2) Rick is not the heaviest or lightest person in the room.
Rick's weight can range from 101 (lightest is 100) to 154 (heaviest is 155)
(Insufficient)

IMO A

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GMATWhizTeam · Answer

Solution 
 Step 1: Analyse Question Stem 
 • Total number of persons in the room, including Rick = 5
• Let us assume that Rick's weight is R pounds.
 o Weight of 5 persons are 100, 120, 135, 155 and R 
• We need to find out if R is equal to 110 or not

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE 
 Statement 1:  The weight of the third heaviest person is equal to the average (arithmetic mean) of the five person's weight.
 • According to this statement: Mean = Median
 o Now, if R = 110, 
  then median = 120
 And Mean  = \frac{100 + 110 +120+135+155}{5} = 124 , which is not equal to median 120.  
• Thus,  R ≠ 110  pounds.  
Hence, statement 1 is sufficient and we can eliminate answer Options B, C and E.

Statement 2:  Rick is not the heaviest or lightest person in the room.
 • According to this statement: 100 < R < 155
 o So, R can be 110 or it can be any other value in the range 100 < R < 155.  
Hence, statement 2 is NOT sufficient.
Thus, the correct answer is  Option A.

Nipungupta9081 · Answer

Answer A

There are 4 people and i we include Rick = 5 
Let's say Rick = 110
We need to find if R is equal to 110 or not. 
Statement 1 :

let's take R = 110

Then 120 should be weight of the 3rd heaviest person. But this is not the average of 5 person's weight. So this implies Rick's weight is not equal to 110.

We can definitely answer NO.

Sufficient

Statement 2 :

Rick's weight can be 110 or 105 or 130.

So insufficient

KaramveerBakshi · Answer

Does Rick weigh 110 pounds?

Statements:

(1) The weight of the third heaviest person is equal to the average (arithmetic mean) of the five person's weight.

Let's consider Rick's weight = 110 pounds.

The list becomes 100,110,120,135,155 ---- (A)

The mean of (A) = 620/5 which is not equal to the weight of the third heaviest person (120 pounds)

So, Rick's weight cannot be 110 for (1) to hold true.

So, Does Rick weigh 110 pounds? No.

Sufficient

(2) Rick is not the heaviest or lightest person in the room.
Rick can have any weight between 100 and 155.

Insufficient

Hence, the answer is Option (A).

sambitspm · Answer

Kindly see the attachment.

CONCEPT is to start assuming things in this question. You need to adapt to this trick to find the sufficient information in such questions.

bumpbot · Answer

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Rick is in a room with 4 other people. If the other people weigh 100,

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GMAT Data Sufficiency (DS) Questions

Rick is in a room with 4 other people. If the other people weigh 100,

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