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Bunuel
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The average (arithmetic mean) of a list of numbers is what percent of the sum of the numbers?

Explanation: mean (M)=Sum of numbers(S)/count of numbers(N)

i.e M=S/N
question asks what is (M/S)*100??

(S1) There are 8 numbers in the list.
given N=8
then (M/S)*100=(1/N)*100
=100/8
=12.5%

Hence S1 is sufficient.

(S2)
The sum of the numbers in the list is 100.
Given S=100
then then (M/S)*100=(1/N)*100
Clearly not enough data to tell exact value
Hence S2 is insufficient.

Thus A is the correct answer.
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