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MarmikUpadhyay
Bunuel
What is the median of the numbers 4, 5, 6, 7, 9, and x?

(1) x > 7
(2) The mean of the six numbers is equal to their median.

Median of 4, 5, 6, 7, 9 and x =?

Statement 1:
x > 7
If x > 7, then 6 and 7 are the two middle terms in ascending order.
Median = Average of 6 and 7 = 6.5
Statement 1 is Sufficient.

Statement 2:
Mean = Median
If x = 2, then Mean = Median = 5.5
If x = 8, then Mean = Median = 6.5
Statement 2 is Not Sufficient.

So, correct answer is option A.

Hi MarmikUpadhyay, Statement 2 states mean = median
We know that if mean = median, then the set has to be evenly spaced. How can we assume x to be 4?
Though your answer seems correct as you have rejected option B with two different options.
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MarmikUpadhyay
Bunuel
What is the median of the numbers 4, 5, 6, 7, 9, and x?

(1) x > 7
(2) The mean of the six numbers is equal to their median.

Median of 4, 5, 6, 7, 9 and x =?

Statement 1:
x > 7
If x > 7, then 6 and 7 are the two middle terms in ascending order.
Median = Average of 6 and 7 = 6.5
Statement 1 is Sufficient.

Statement 2:
Mean = Median
If x = 2, then Mean = Median = 5.5
If x = 8, then Mean = Median = 6.5
Statement 2 is Not Sufficient.

So, correct answer is option A.

Hi MarmikUpadhyay, Statement 2 states mean = median
We know that if mean = median, then the set has to be evenly spaced. How can we assume x to be 4?
Though your answer seems correct as you have rejected option B with two different options.

Look if x < 5, Median = 5.5 and if Median > 7 Median = 6.5
For above two cases, Mean can be 5.5 for x = 2 and 6.5 for x = 8.
We can have one more case where 5 < x < 7, but it will be tedious and unnecessary as we got two different values of x, so no need for this case.
I hope it helps!

P.S. We didn't assume x to be anything, we can go in reverse manner like I showed above.
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What is the median of the numbers 4, 5, 6, 7, 9, and x?

Stat1: x > 7
x can be 8, 9.... still median will depend on 6 and 7. Sufficient

Stat2: The mean of the six numbers is equal to their median.
It means x can be on left side or right of mid number, so x can be 2 or 8. Then median will change, as sum will. Not sufficient

So, I think A. :)
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Hello,

The questions states mean = median. Does this not mean the sequence is an arithmetic progression?

This gives us that x has to be equal to 8. Then, Statement 2 is also suffices.

Thoughts?
Bunuel


What is the median of the numbers 4, 5, 6, 7, 9, and x?

The median of a set with even number of terms is the average of two middle terms when arranged in ascending/descending order.

(1) x > 7 --> two middle terms are 6 and 7, thus median=(6+7)/2=6.5. Sufficient.

(2) The mean of the six numbers is equal to their median.

If \(x\leq{5}\), then two middle terms are 5 and 6, thus median=(5+6)/2=5.5. In this case mean=(4+5+6+7+9+x)/6=5.5 --> x=2. Possible scenario.
If \(x\geq{7}\), then two middle terms are 6 and 7, thus median=(6+7)/2=6.5. In this case mean=(4+5+6+7+9+x)/6=6.5 --> x=8. Possible scenario.
Not sufficient.

Answer: A.

P.S. For (2): if \(5<x<7\), then two middle terms are x and 6, thus median=(x+6)/2. In this case mean=median=(4+5+6+7+9+x)/6=(x+6)/2 --> x=6.5. Also, possible scenario.

Similar questions to practice:
https://gmatclub.com/forum/if-set-s-con ... 32570.html
https://gmatclub.com/forum/what-is-the- ... 37225.html
https://gmatclub.com/forum/if-the-range ... 27089.html
https://gmatclub.com/forum/the-sum-of-t ... 27755.html
https://gmatclub.com/forum/given-the-as ... 15675.html

Hope it helps.
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ShivenDhir1
Hello,

The questions states mean = median. Does this not mean the sequence is an arithmetic progression?

This gives us that x has to be equal to 8. Then, Statement 2 is also suffices.

Thoughts?


In an evenly spaced set (arithmetic progression), the median is equal to the mean, although the reverse isn't necessarily true. For example, consider the set {-1, 1, 2, 3, 5} where the median and mean are both 2, yet the set is not evenly spaced.
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