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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
Dear expert
Can the answer be D .
I understand the question asking whether 0<n<7
From Statement 1 , we get 1=<n<5, hence n is within 0<n<7 , thus it is sufficient
From statement 2, we get 1<n<=5, n is within 0<n<7, thus it is sufficient ,
Am I understand it wrongly
Appreciate could shed some lights
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
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apple08 wrote:
Dear expert
Can the answer be D .
I understand the question asking whether 0<n<7
From Statement 1 , we get 1=<n<5, hence n is within 0<n<7 , thus it is sufficient
From statement 2, we get 1<n<=5, n is within 0<n<7, thus it is sufficient ,
Am I understand it wrongly
Appreciate could shed some lights



Hi,
you do not get what you are assuming above.
i'll try to explain where you are going wrong..

If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?
(1) The median of the numbers in S is less than 5.
median means the central value..
lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median is less than 5....

so n can take any value less than 5..
if its 4... -2,1,4,5,8.... median is 4
if its 0... -2,0,1,5,8.... median is 1
so if n is between 1 and 5, n is the median and if n < =1, median will be 1...
so n <5..... insuff, as we are asked if 0 < n < 7..
n can be anything -100,-50

(2) The median of the numbers in S is greater than 1..
now lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median >1....

so n can take any value >1..
if its 2... -2,1,2,5,8.... median is 2
if its 6 ... -2,0,5,6,8.... median is 5
so if n is between 1 and 5, n is the median and if n > =5, median will be 5...
so n >1..... insuff, as we are asked if 0 < n < 7..
n can be anything 70,6 etc..

combined we know the median is between 1 and 5..
this means n will be the meadian..
so n is between 1 and 5, suff
C
hope helps
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
Expert Reply
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?

(1) The median of the numbers in S is less than 5.
(2) The median of the numbers in S is greater than 1.


When it comes to inequality for DS questions, if range of que include range of con, it means the con is sufficient.
In the original condition, there is 1 variable(n), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer.
For 1), if n<5, the range of que doesn’t include the range of con, which is not sufficient.
For 2), if 1<n, the range of que doesn’t include the range of con, which is not sufficient.
When 1) & 2), they become 1<n<5. The range of que includes the range of con, which is sufficient. Therefore, the answer is C.



 For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
chetan2u wrote:
apple08 wrote:
Dear expert
Can the answer be D .
I understand the question asking whether 0<n<7
From Statement 1 , we get 1=<n<5, hence n is within 0<n<7 , thus it is sufficient
From statement 2, we get 1<n<=5, n is within 0<n<7, thus it is sufficient ,
Am I understand it wrongly
Appreciate could shed some lights



Hi,
you do not get what you are assuming above.
i'll try to explain where you are going wrong..

If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?
(1) The median of the numbers in S is less than 5.
median means the central value..
lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median is less than 5....

so n can take any value less than 5..
if its 4... -2,1,4,5,8.... median is 4
if its 0... -2,0,1,5,8.... median is 1
so if n is between 1 and 5, n is the median and if n < =1, median will be 1...
so n <5..... insuff, as we are asked if 0 < n < 7..
n can be anything -100,-50

(2) The median of the numbers in S is greater than 1..
now lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median >1....

so n can take any value >1..
if its 2... -2,1,2,5,8.... median is 2
if its 6 ... -2,0,5,6,8.... median is 5
so if n is between 1 and 5, n is the median and if n > =5, median will be 5...
so n >1..... insuff, as we are asked if 0 < n < 7..
n can be anything 70,6 etc..

combined we know the median is between 1 and 5..
this means n will be the meadian..
so n is between 1 and 5, suff
C
hope helps


Hi Chetan,

I also tried the same approach and marked E when I deduced 1<n<5 as question is stating if 0<n<7
ISN'T 1<n<5 subset of 0<n<7 , so how can we say n exists between 0 and 7

Please resolve the confusion
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
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kanigmat011 wrote:
chetan2u wrote:
apple08 wrote:
Dear expert
Can the answer be D .
I understand the question asking whether 0<n<7
From Statement 1 , we get 1=<n<5, hence n is within 0<n<7 , thus it is sufficient
From statement 2, we get 1<n<=5, n is within 0<n<7, thus it is sufficient ,
Am I understand it wrongly
Appreciate could shed some lights



Hi,
you do not get what you are assuming above.
i'll try to explain where you are going wrong..

If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?
(1) The median of the numbers in S is less than 5.
median means the central value..
lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median is less than 5....

so n can take any value less than 5..
if its 4... -2,1,4,5,8.... median is 4
if its 0... -2,0,1,5,8.... median is 1
so if n is between 1 and 5, n is the median and if n < =1, median will be 1...
so n <5..... insuff, as we are asked if 0 < n < 7..
n can be anything -100,-50

(2) The median of the numbers in S is greater than 1..
now lets put these numbers in ascending order..
-2,1,5,8 and n ; we are given median >1....

so n can take any value >1..
if its 2... -2,1,2,5,8.... median is 2
if its 6 ... -2,0,5,6,8.... median is 5
so if n is between 1 and 5, n is the median and if n > =5, median will be 5...
so n >1..... insuff, as we are asked if 0 < n < 7..
n can be anything 70,6 etc..

combined we know the median is between 1 and 5..
this means n will be the meadian..
so n is between 1 and 5, suff
C
hope helps


Hi Chetan,

I also tried the same approach and marked E when I deduced 1<n<5 as question is stating if 0<n<7
ISN'T 1<n<5 subset of 0<n<7 , so how can we say n exists between 0 and 7

Please resolve the confusion


Hi kani,
any value of n is between 1 and 5, this has to be true for whatever this set is a subset of...
say n is 2 or 3, it will always be between the main set..
so if you get your answer as 1<n<5 and the main Q asks you if n is a positive integer, that would be true since any value of n will be true

the vice versa will not be correct..
that is we get 0<n<7 and answer asks if 1<n<5,.. it is not suff, as it doe snot contain 6,5 and 1...
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
Point Noted
Thanks Chetan
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ? [#permalink]
If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?
(1) The median of the numbers in S is less than 5.
(2) The median of the numbers in S is greater than 1.

Given numbers are
-2 1 5 8 and n
Statement 1:
if median is less than 5
it can be 1 or n
if it is 1 => n<1
if it is n => n<5
not sufficient

Statement 2:
median is greater than 1
=>median can be 5 or n
if 5 =>n>5
if n => 1<n<5
not sufficient

Together
median is >1 and <5
=> n is 1<n<5
thus answer option C
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ? [#permalink]
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HarveyKlaus wrote:
If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?

(1) The median of the numbers in S is less than 5.
(2) The median of the numbers in S is greater than 1.


Hi

Arrange the numbers in ascending order..
-2,1,5,8...
1) median is less than 5..
So n can be anything below 5 that is n<5..
If n is between 1 and 5, median is n,
And if n<1, median is 1
So n can be in the range 0 to 7 or less than 0
Insuff.
2) median is greater than 1.
So n >1..
If n is between 1 and 5, median is n, otherwise 5.
Insuff
Combined n<5 and n>1, so 1<n<5..
So ans is YES for 0<n<7
Suff

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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ? [#permalink]
HarveyKlaus wrote:
If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?

(1) The median of the numbers in S is less than 5.
(2) The median of the numbers in S is greater than 1.


Set \(S = \{-2, 1, 5, 8, n \}\)

(1) If median of the numbers in S is less than 5, we have n<5.

If \(n<-2\), set \(S = \{ n, -2, 1, 5, 8 \}\). Median of S is 1.
If \(-2<n<1\), set \(S = \{ -2, n, 1, 5, 8 \}\). Median of S is 1.
If \(1<n<5\), set \(S = \{ -2, 1, n, 5, 8 \}\). Median of S is n<5.

In all cases, which have median of S is less than 5, we have \(n<5\). This means n coud be in \((0, 7)\) or could be out of \((0, 7)\).
Insufficient.

(2) If median of the numbers in S is greater than 1, we have \(n>1\).
If \(n>8\), set \(S = \{ -2, 1, 5, 8, n \}\). Median of S is 5.
If \(5<n<8\), set \(S = \{ -2, 1, 5, n, 8 \}\). Median of S is 5.
If \(1<n<5\), set \(S = \{ -2, 1, n, 5, 8 \}\). Median of S is \(n>1\).

In all cases, which have median of S is greater than 1, we have \(n>1\). This means n coud be in \((0, 7)\) or could be out of \((0, 7)\).
Insufficient.

Combine (1) & (2)
(1) lead to \(n<5\)
(2) lead to \(n<1\)
(1) & (2) lead to \(1<n<5\), means that \(0<n<7\). Sufficient
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
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Stiv wrote:
If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < n < 7 ?

(1) The median of the numbers in S is less than 5.
(2) The median of the numbers in S is greater than 1.

\(S = \left\{ { - 2,1,5,8} \right\} \cup \left\{ n \right\}\)

\(?\,\,\,:\,\,\,0 < n < 7\)


\(\left( 1 \right)\,\,\,{\rm{Med}}\left( S \right) < 5\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,n = 0\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\,\,\,\,\,\,\,\left[ {Med\left( S \right) = {\rm{Med}}\left( {\left\{ { - 2,0,1,5,8} \right\}} \right) = 1} \right]\,\, \hfill \cr \\
\,{\rm{Take}}\,\,n = 1\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\,\,\,\,\,\,\,\,\left[ {Med\left( S \right) = {\rm{Med}}\left( {\left\{ { - 2,1,1,5,8} \right\}} \right) = 1} \right]\,\,\, \hfill \cr} \right.\,\)


\(\left( 2 \right)\,\,\,{\rm{Med}}\left( S \right) > 1\,\,\,\left\{ \matrix{\\
\,{\rm{Take}}\,\,n = 7\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\,\,\,\,\,\,\,\left[ {Med\left( S \right) = {\rm{Med}}\left( {\left\{ { - 2,1,5,7,8} \right\}} \right) = 5} \right]\,\, \hfill \cr \\
\,{\rm{Take}}\,\,n = 6\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\,\,\,\,\,\,\,\,\left[ {Med\left( S \right) = {\rm{Med}}\left( {\left\{ { - 2,1,5,6,8} \right\}} \right) = 5} \right]\,\,\, \hfill \cr} \right.\)


\(\left( {1 + 2} \right)\,\,\,\,1 < {\rm{Med}}\left( S \right) < 5\,\,\,\,\,\,\mathop \Rightarrow \limits^{\left( * \right)} \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle\)

\(\left( * \right)\,\,\left\{ \matrix{\\
\,n \le 0\,\,\, \Rightarrow \,\,\,\,Med\left( S \right) = 1\,\,,\,\,\,\,{\rm{impossible}} \hfill \cr \\
\,n \ge 7\,\,\, \Rightarrow \,\,\,\,Med\left( S \right) = 5\,\,,\,\,\,\,{\rm{impossible}} \hfill \cr} \right.\,\,\,\,\,\,\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: If set S consists of the numbers 1, 5, -2, 8, and n, is 0 < [#permalink]
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