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In a survey of an Olympic team members, 1/6th of them said they do not watch movies during their free time, of those, 3/4th said they also do not play video games during their free time. Is the number of the Olympic team members who do not play video games equal to 90 ?


Let us fill up the data in 2*2 matrix


MNMTotal
v\(\frac{x}{24}\)
NVy\(\frac{x}{8}\)
Total\(\frac{5x}{6}\)\(\frac{x}{6}\)x

We have to answer: Is \(y+\frac{x}{8}=90\)?

(1) 210 members of the Olympic team said that they watch movies and play video games during their free time


MNMTotal
V210\(\frac{x}{24}\)
NVy\(\frac{x}{8}\)
Total\(\frac{5x}{6}\)\(\frac{x}{6}\)x

\(210+y=\frac{5x}{6}…….y=\frac{5x}{6}-210\).
Thus, \(y+\frac{x}{8}=\frac{5x}{6}-210+\frac{x}{8}=\frac{23x}{24}-210\)
Can \(\frac{23x}{24}-210=90…….\frac{23x}{24}=300……x=\frac{300*24}{23}\).
NO, as x will not be an integer.
Sufficient

(2) 15 members of the Olympic team said that they play video games but do not watch movies during their free time

MNMTotal
V\(\frac{x}{24}=15\)
NVy\(\frac{x}{8}\)
Total\(\frac{5x}{6}\)\(\frac{x}{6}\)x
So we get \(\frac{x}{24}=15…..x=360\)
\(\frac{x}{8}=\frac{360}{8}=45\)
Is y+45=90?

Yes and no both as y can take values such as 45, 46, 50 etc
Insufficient


A
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