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Key Step: Factor the expression first.

x4 − 10x2 + 9 = (x2 − 1)(x2 − 9) = (x−1)(x+1)(x−3)(x+3)

So y = (x−1)(x+1)(x−3)(x+3)

For y to be a multiple of 30, we need y divisible by 2, 3, and 5.

Critical Insight: Since x is an odd prime > 3, all four factors are EVEN (divisibility by 2 ✓) and at least one factor is always divisible by 3 (✓). The only question is: Is the product divisible by 5?

The product is divisible by 5 unless x itself is a multiple of 5 (i.e., x = 5).

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Statement 1: x is prime with remainder 1 when divided by 5

→ x ≡ 1 (mod 5), which means (x − 1) is divisible by 5
→ Valid primes: 11, 31, 41, 61... (none equals 5)
→ Product is always divisible by 2 × 3 × 5 = 30

SUFFICIENT

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Statement 2: x is prime with remainder 5 when divided by 6

→ Valid primes: 5, 11, 17, 23, 29...

Case 1: x = 5
y = (4)(6)(2)(8) = 384 = 27 × 3
NOT divisible by 5 → NOT a multiple of 30

Case 2: x = 11
y = (10)(12)(8)(14) = 13,440
Divisible by 30 ✓

Two valid cases → Two different answers

NOT SUFFICIENT

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Answer: A
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