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ktzsikka
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chetan2u
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Here is the OE

Solution:
Solution
Step 1: Analyse Question Stem
x is a positive integer.
x is a product of p distinct prime numbers.
\(x=P_1*P_2*P_3…P_p=P \) where P is a prime number.
We need to find the value of p.

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: x is divisible by exactly 8 positive integers.

Since, x can be written as \(P_1*P_2*P_3…P_p\)
Number of factors of x =(1+1)*(1+1)*……..(1+1) \ upto \ p \ times=2^p(1+1)∗(1+1)∗……..(1+1) upto p times=\(2^p\)


As per the given statement:

Number of factors of x = 8
Thus,\( 2^p=8= 2^3 \)

 ⟹ p = 3
Hence, statement 1 is sufficient and we can eliminate answer options B, C and E

Statement 2: : x and \(2* 3^3∗3\) has same numbers of divisors.

Number of divisors of x = number of divisors of \(2* 3^3 \) = \((1+1) *(3+1) =8\)
\(2^p=8= 2^3 \)

Thus, p = 3
Hence, statement 2 is also sufficient and the correct answer is Option D.
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ktzsikka
Here is the OE

Solution:
Solution
Step 1: Analyse Question Stem
x is a positive integer.
x is a product of p distinct prime numbers.
\(x=P_1*P_2*P_3…P_p=P \) where P is a prime number.
We need to find the value of p.

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: x is divisible by exactly 8 positive integers.

Since, x can be written as \(P_1*P_2*P_3…P_p\)
Number of factors of x =(1+1)*(1+1)*……..(1+1) \ upto \ p \ times=2^p(1+1)∗(1+1)∗……..(1+1) upto p times=\(2^p\)


As per the given statement:

Number of factors of x = 8
Thus,\( 2^p=8= 2^3 \)

 ⟹ p = 3
Hence, statement 1 is sufficient and we can eliminate answer options B, C and E

Statement 2: : x and \(2* 3^3∗3\) has same numbers of divisors.

Number of divisors of x = number of divisors of \(2* 3^3 \) = \((1+1) *(3+1) =8\)
\(2^p=8= 2^3 \)

Thus, p = 3
Hence, statement 2 is also sufficient and the correct answer is Option D.

If it is 2^3, there is only one distinct prime number and that is 2.
How can p be 3.

It is a poor quality question with equally poor quality of solution.
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chetan2u
ktzsikka
Here is the OE

Solution:
Solution
Step 1: Analyse Question Stem
x is a positive integer.
x is a product of p distinct prime numbers.
\(x=P_1*P_2*P_3…P_p=P \) where P is a prime number.
We need to find the value of p.

Step 2: Analyse Statements Independently (And eliminate options) – AD/BCE
Statement 1: x is divisible by exactly 8 positive integers.

Since, x can be written as \(P_1*P_2*P_3…P_p\)
Number of factors of x =(1+1)*(1+1)*……..(1+1) \ upto \ p \ times=2^p(1+1)∗(1+1)∗……..(1+1) upto p times=\(2^p\)


As per the given statement:

Number of factors of x = 8
Thus,\( 2^p=8= 2^3 \)

 ⟹ p = 3
Hence, statement 1 is sufficient and we can eliminate answer options B, C and E

Statement 2: : x and \(2* 3^3∗3\) has same numbers of divisors.

Number of divisors of x = number of divisors of \(2* 3^3 \) = \((1+1) *(3+1) =8\)
\(2^p=8= 2^3 \)

Thus, p = 3
Hence, statement 2 is also sufficient and the correct answer is Option D.

If it is 2^3, there is only one distinct prime number and that is 2.
How can p be 3.

It is a poor quality question with equally poor quality of solution.

Okay.. Now I understood your PoV.
Yes, 2x2x2 is also a product of (1) distinct prime number. But I think the question maker must have thought that the factors should not be repetitive. Maybe "different" should also be added to the question, to clear the ambiguity.
And yeah, OE justifies the question, so it's also incorrect.

Posted from my mobile device

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