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02 Mar 2022, 09:30
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In a certain class, the ratio of left-handed students to right-handed students is 5:4. There are no ambidextrous students in the class: every student is either left-handed or right-handed. How many left-handed students are there?
(1) If four new right-handed students joined the class, the number of right-handed students would increase by 20%.
(2) If the number of left-handed students increases by 50%, then after such an increase, the probability that a randomly chosen student would be a right-handed student would be 8/23.
Are You Up For the Challenge: 700 Level Questions
(1) If four new right-handed students joined the class, the number of right-handed students would increase by 20%.
(2) If the number of left-handed students increases by 50%, then after such an increase, the probability that a randomly chosen student would be a right-handed student would be 8/23.
Are You Up For the Challenge: 700 Level Questions
06 Mar 2022, 21:40
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Bunuel
We can take the number of left-handed students and right-handed students as 5x and 4x.
(1) If four new right-handed students joined the class, the number of right-handed students would increase by 20%.
\(4x+4 = 1.2*4x\)
\(0.2x=1\) or \(x=5\).
Left handed students = \(5*5 = 25\)
(2) If the number of left-handed students increases by 50%, then after such an increase, the probability that a randomly chosen student would be a right-handed student would be 8/23.
After increase, the number of left-handed students becomes 1.5*5x
The probability of choosing right handed student = \(\frac{4x}{4x+7.5x }= \frac{8}{23}\)
\(\frac{4x}{11.5x }=\frac{ 8}{23}.....\frac{8}{23}=\frac{8}{23}\)
We cannot find x.
A
23 May 2023, 02:07
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In the second statement, can we set x=2, numerator 4x becomes 8 and denominator 11.5x becomes 23, is this valid?
