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Hoozan
In a certain infinite sequence n, \(n_{1}\) = 7, \(n_{2}\) = 70, \(n_{3}\) = 700 ... \(n_{x}\) = 10(\(n_{x-1}\))

(1) j is a prime number.
(2) j is a factor of more than one member of the sequence

Hi Hoozan,

There needs to be a question in this question :)

Opps! Thanks for bringing it to my attention. I have made the required edits
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In a certain infinite sequence n, \(n_{1}\) = 7, \(n_{2}\) = 70, \(n_{3}\) = 700 ... \(n_{x}\) = 10(\(n_{x-1}\)), is the integer j a factor of every member of n?

(1) j is a prime number.
(2) j is a factor of more than one member of the sequence

Thanks for adding the question -- it isn't too different from the one I answered above ("what is j?"), because the only positive factors of every term in the sequence are 1 and 7. So the question is really asking "Is j = 1 or j = 7?" and when we use Statement 1, we know j is not 1, so the question becomes "Is j = 7?" Even with both Statements, j can be 2, 5 or 7, so we can't answer the question, and the answer is E.
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In a certain infinite sequence n, \(n_{1}\) = 7, \(n_{2}\) = 70, \(n_{3}\) = 700 ... \(n_{x}\) = 10(\(n_{x-1}\)), is the integer j a factor of every member of n?

We are looking at a sequence wherein each subsequent element is 10 times previous element and the sequence starts with 7.

Is the integer j a factor of every member of n? or Is the integer j a factor of 7?, as 7 is the smallest in the sequence.
In other words, is j one of the two - 1 or 7.

(1) j is a prime number.
j could be any prime number.

(2) j is a factor of more than one member of the sequence
The sequence consists of 7, and thereafter, product of 7 and successive multiples of 10.
So, j can be 1, 2, 5 or 7.


Combined,
j could still be 2, 5 or 7.


E
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