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gmatophobia
Bunuel
12 jurors must be picked from a pool of n potential jurors. It m of the potential jurors are rejected by the defense council and the prosecuting attorney, how many different possible juries could be picked from the remaining potential jurors?

Statement 1

If one less potential juror had been rejected, it would be possible to create 13 different juries

n-m+1 C 12 = 13

n - m + 1 = 13

n - m = 12

Hence we have 12 jurors left and we need 12 jurors. They can be selected in 1 way.


Option D

would you kindly elaborate how you deduced n-m+1 to be 13 from (n-m+1)C(12) =13.... ?
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gmatophobia
Bunuel
12 jurors must be picked from a pool of n potential jurors. It m of the potential jurors are rejected by the defense council and the prosecuting attorney, how many different possible juries could be picked from the remaining potential jurors?

(1) If one less potential juror had been rejected, it would be possible to create 13 different juries

(2) n = m + 12

Statement 1

If one less potential juror had been rejected, it would be possible to create 13 different juries

n-m+1 C 12 = 13

n - m + 1 = 13

n - m = 12

Hence we have 12 jurors left and we need 12 jurors. They can be selected in 1 way.

Statement 1

n = m + 12

n - m = 12

Hence we have 12 jurors left and we need 12 jurors. They can be selected in 1 way.

Option D


How it is possible to take statement 1 like this? there is no information about the size of the jury... then how we can assume each jury contains 1 juro?
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could you please tell how we take n-m+1 =13 here after we get (n-m+1) C 12 = 13 ?
thank you
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Abhijeet089
could you please tell how we take n-m+1 =13 here after we get (n-m+1) C 12 = 13 ?
thank you


Think: <what number> C 12 yields 13?

Say,

xC12 = 13.

- Can x be <12? Nope. Mathematically not possible to select 12 jurors from a number of jurors less than 12.
- Can x be 12? Nope. 12C2 = 1, not 13.
- Can x be 13? Yes. 13C12 = 13.
- Can x be 14? Nope. 14C12 = 14 x 13 / 2 = 91.
- Can x be 15? Nope. 15C12 = an even bigger number (455)


Observe. x cannot be lesser than 12. As x goes above 13, xC12 keeps increasing beyond 13. The only legit x value is x = 13.

x can only be 13.

i.e., n-m+1 = 13.

Here is another way to figure out that n-m+1 = 13.



---
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