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24 Mar 2023, 23:52
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
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Question Stats:
41% (01:22) correct
59%
(01:23)
wrong
based on 264
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If the sequence v, w, x, y, and z is in Arithmetic progression, is the sequence of numbers: a, b, c, d, and e in arithmetic progression?
(A) The sequence a, b, c, d, and e is formed by squaring each term in the sequence v, w, x, y, and z
(B) All terms in the sequence v, w, x, y, and z are integers.
(A) The sequence a, b, c, d, and e is formed by squaring each term in the sequence v, w, x, y, and z
(B) All terms in the sequence v, w, x, y, and z are integers.
25 Mar 2023, 00:13
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ChandlerBong
Statement 1:
(A) The sequence a, b, c, d, and e is formed by squaring each term in the sequence v, w, x, y, and z
Case 1:
Let v = x = w = y = z = 0. As per statement 1, a = b = c = d = e = 0
Is the sequence of numbers: a, b, c, d, and e in arithmetic progression - Yes !
Case 2:
Let v = 1, x =2, w =3, y =4, z = 5. As per statement 1, a =1, b =4, c = 9, d =16, e = 25
Is the sequence of numbers: a, b, c, d, and e in arithmetic progression - No!
As we are getting two contradicting answers to the question, the statement alone is not sufficient.
Statement 2:
(B) All terms in the sequence v, w, x, y, and z are integers.
This statement doesn't provide any information. We can take both cases in Statement 1, to arrive at two contradicting answers.
Hence, eliminate B,
Combined:
At this stage, the statements combined need not be even evaluated as Statement B didn't provide anything meaningful.
Combined: both cases presented in statement 1 are still valid.
Option E
04 Nov 2025, 06:20
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