Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2601:30 AM EDT
-02:30 AM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
May 0111:00 AM PDT
-12:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
12 May 2023, 03:06
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:00) correct
27%
(02:23)
wrong
based on 48
sessions
History
Date
Time
Result
Not Attempted Yet
If n is a positive integer, is n(n^2 - 1) divisible by 42?
(1) n^3 is divisibly by 8.
(2) n is divisibly be 21.
Try this fresh challenging question from our new edition of GMAT Club Tests.
(1) n^3 is divisibly by 8.
(2) n is divisibly be 21.
Try this fresh challenging question from our new edition of GMAT Club Tests.
|
Experience GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
12 May 2023, 03:45
Kudos
Bookmarks
Bunuel
\(n(n^2-1)\) = n(n+1)(n-1)
n(n+1)(n-1) represents the product of three consecutive integers. Hence \( n(n+1)(n-1)\) will always be divisible by 6.
Question: Is n(n^2 - 1) divisible by 42 ?
42 = 7 * 3 * 2
As \( n(n+1)(n-1)\) will always be divisible by 6, we need to determine if \( n(n+1)(n-1)\) is divisible by 7.
Target Question: Is \( n(n+1)(n-1)\) divisible by 7?
Statement 1
(1) \(n^3\) is divisibly by 8.
While we can infer that n is even, we can't say for sure that n contains a 7. In other words, the statement is not sufficient to conclude whether 7 is a factor of n.
Case 1: If n is a multiple of 7, then the answer to the target question is Yes.
Case 2: If n is not a multiple of 7, then the answer to the target question is No.
As we are getting two answers to the target question, the statement alone is not sufficient. Eliminate A and D.
Statement 2
(2) \(n\) is divisibly be 21.
If n is divisible by 21, then n must be a multiple of 7. Put otherwise, 7 is a factor of n.
The statement is enough to answer a definite Yes to the target question - "Is \( n(n+1)(n-1)\) divisible by 7?"
Option B
Archit3110
Major Poster
12 May 2023, 07:04
Kudos
Bookmarks
target is s
n*(n+1)*(n-1)/ (2*3*7)
#1
n^3 is divisible by 2^3
n can be 2,4,6
we get yes and no to target
#2
n is divisibly be 21
n = 21,42 or its multiple
n*(n+1)*(n-1)/ (2*3*7)
and for every value of n we get even value which will be divisible by 2
so sufficient
option B
n*(n+1)*(n-1)/ (2*3*7)
#1
n^3 is divisible by 2^3
n can be 2,4,6
we get yes and no to target
#2
n is divisibly be 21
n = 21,42 or its multiple
n*(n+1)*(n-1)/ (2*3*7)
and for every value of n we get even value which will be divisible by 2
so sufficient
option B
Bunuel
