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06 Jul 2023, 01:31
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:15) correct
20%
(01:58)
wrong
based on 144
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If machine A and machine B can finish the task in 4 hours when working together at their constant rates, in how many hours can machine B finish the task alone?
(1) Machine A can finish the task in 6 hours alone
(2) The hours that it takes machine B to finish the task alone is 6 hours longer than the hours that it takes machine A to finish the task alone
(1) Machine A can finish the task in 6 hours alone
(2) The hours that it takes machine B to finish the task alone is 6 hours longer than the hours that it takes machine A to finish the task alone
06 Jul 2023, 02:32
Kudos
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My Answer is D
1) Suff -
A can complete 1/6th of a task in an hour
1/6 + B = 1/4
Solve for B -> 12 hours
2) Suff -
A + B = 1/4 and B = A+6
1/x + 1/(x+6) = 1/4
Solve for x
x^2 - 2x - 24 = 0
(x-6)(x+4) = 0
x cant be negative
so x = 6. B takes 6 hours more than A. B takes 12 hours.
D
1) Suff -
A can complete 1/6th of a task in an hour
1/6 + B = 1/4
Solve for B -> 12 hours
2) Suff -
A + B = 1/4 and B = A+6
1/x + 1/(x+6) = 1/4
Solve for x
x^2 - 2x - 24 = 0
(x-6)(x+4) = 0
x cant be negative
so x = 6. B takes 6 hours more than A. B takes 12 hours.
D
07 Jul 2023, 01:49
Kudos
Bookmarks
Keep in mind that we only have to check whether question can be solved or not. We need not find exact answer. This will save tons of time in exam.
A and B's together working rate is known which is 1/4 task per hour (as in 4 hour, 1 unit of task is done). Following equation is valid for individual working rate:
\(\frac{1}{(A+B)} = \frac{1}{A} + \frac{1}{B}\)
Stmt 1: We now know A's working rate, which is 1/6 task per hour. So clearly B's working rate can be calculated hence sufficient.
Stmt 2: Difference between A and B's completion hour is given. So assume A takes x hours then B takes x+6 hours, again we have one equation and one variable hence sufficient.
Hence correct answer is D.
A and B's together working rate is known which is 1/4 task per hour (as in 4 hour, 1 unit of task is done). Following equation is valid for individual working rate:
\(\frac{1}{(A+B)} = \frac{1}{A} + \frac{1}{B}\)
Stmt 1: We now know A's working rate, which is 1/6 task per hour. So clearly B's working rate can be calculated hence sufficient.
Stmt 2: Difference between A and B's completion hour is given. So assume A takes x hours then B takes x+6 hours, again we have one equation and one variable hence sufficient.
Hence correct answer is D.
Bunuel
