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Bunuel
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Bunuel
The cost of a certain school trip was $16 for each child and $24 for each adult. What was the ratio of the number of children to the number of adults on the trip?

(1) The ratio of the total cost of the trip for all children to the total cost of the trip for all adults was 8 to 3.
(2) The total cost of the trip for all children and adults together was $2,200.

The prices were $16 per child and $24 per adult, and we need to answer the question:

# of children (c) : # of adults (a)= ?

Statement One Alone:

=> The ratio of the total cost of the trip for all children to the total cost of the trip for all adults was 8 to 3.

Total cost for children : Total cost for adults = 8 : 3

16c/24a = 8/3
2c/3a = 8/3
c/a = 4/1 => c : a = 4 : 1

Statement one is sufficient. Eliminate answer choices B, C, and E.

Statement Two Alone:

=> The total cost of the trip for all children and adults together was $2,200.

16c + 24a = 2,200
2c + 3a = 275

If there were 100 children and 25 adults, then c : a = 100 : 25 = 4 : 1.

Whereas, if there were 25 children and 75 adults, then c : a = 25 : 75 = 1 : 3.

Statement two is not sufficient.

Answer: A
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I always have trouble during the exam to check such possibilities of different numbers that can satisfy an equation. I end up either picking the wrong combos, getting only 1 pair to work and calling such a statement sufficient OR end up wasting time either way. Any work arounds or suggestions would be very helpful JeffTargetTestPrep !
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KS1409
I always have trouble during the exam to check such possibilities of different numbers that can satisfy an equation. I end up either picking the wrong combos, getting only 1 pair to work and calling such a statement sufficient OR end up wasting time either way. Any work arounds or suggestions would be very helpful JeffTargetTestPrep !
­Second that. KarishmaB chetan2u gmatophobia Bunuel GMATCoachBen Experts, if you could please advise.
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KS1409
I always have trouble during the exam to check such possibilities of different numbers that can satisfy an equation. I end up either picking the wrong combos, getting only 1 pair to work and calling such a statement sufficient OR end up wasting time either way. Any work arounds or suggestions would be very helpful JeffTargetTestPrep !
­Second that. KarishmaB chetan2u gmatophobia Bunuel GMATCoachBen Experts, if you could please advise.

If you are facing issues with Diophantine equations, you can refer to the blog post in Karishma’s response above, or watch a video on the topic on YouTube by Anthony Ritz. The video is titled: Linear Diophantine Equations: Ax + By = C, and is hosted on the GMAT club channel.
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is there a way of quickly finding out if an expression such as 2a + 3b = 275 has multiple solutions? , not this one in particular but maybe something harder
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Borrat
is there a way of quickly finding out if an expression such as 2a + 3b = 275 has multiple solutions? , not this one in particular but maybe something harder
You don't have to remember this every time. Just remember that a single linear equation with two different equation in addition typically have many solution.
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