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sset92
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If p and q are positive integers such that q > p, what is the remainder when q is divided by p?

(1) q = pm + 4, where m is a positive integer.
Two variables many possibilities.
1. q = 32, p = 7, m = 4, r = 4
2. q = 30, p = 2, m = 13, r = 0

INSUFFICIENT.

(2) p < 4
Nothing about q so two variables with infinite possibilities.

INSUFFICIENT.

Together 1 and 2
1. q = 30, p = 2, m = 13, r = 0
2. q = 28, p = 3, m = 24, r = 1

INSUFFICIENT.

Answer E.
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Why is statement 1 insuff. Isn't it of the form Dividend=Divisor(Quotient) + Remainder?
sset92
If p and q are positive integers such that q > p, what is the remainder when q is divided by p?

(1) q = pm + 4, where m is a positive integer.
(2) p < 4
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vatsal240102
Why is statement 1 insuff. Isn't it of the form Dividend=Divisor(Quotient) + Remainder?
sset92
If p and q are positive integers such that q > p, what is the remainder when q is divided by p?

(1) q = pm + 4, where m is a positive integer.
(2) p < 4
You got it right when you say that. But don't you think that why would GMAT or any standardised test ask for a remainder by giving a simple
"Dividend=Divisor(Quotient) + Remainder" form. If it's given in such a form and asks for a simple(as it looks in the first impression) remainder, then questions must be raised.

Even after that if you don't understand then look clearly in the St. 1 and think of 4 which is remainder here as it looks like(more so when m too is an integer).

Here, there are three variables q,p and m. Assuming two would give us the third. So, with two variables(p and m) having infinite possibilities, there is high chances of getting infinite number of remainder when the third variable is divided by one of the two - in our case when q is divided by p.

But we need only two different values of remainder to make it insufficient. The statement in that form is just for trapping the over-smartness.:)

HTHs.
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I get your point about it being too direct but according to Question stem & Statement 1, theoretically shouldn't it be true that the values of p,q & m will always be such that the remainder has to be 4? How do we disprove it to eliminate A
unraveled
vatsal240102
Why is statement 1 insuff. Isn't it of the form Dividend=Divisor(Quotient) + Remainder?
sset92
If p and q are positive integers such that q > p, what is the remainder when q is divided by p?

(1) q = pm + 4, where m is a positive integer.
(2) p < 4
You got it right when you say that. But don't you think that why would GMAT or any standardised test ask for a remainder by giving a simple
"Dividend=Divisor(Quotient) + Remainder" form. If it's given in such a form and asks for a simple(as it looks in the first impression) remainder, then questions must be raised.

Even after that if you don't understand then look clearly in the St. 1 and think of 4 which is remainder here as it looks like(more so when m too is an integer).

Here, there are three variables q,p and m. Assuming two would give us the third. So, with two variables(p and m) having infinite possibilities, there is high chances of getting infinite number of remainder when the third variable is divided by one of the two - in our case when q is divided by p.

But we need only two different values of remainder to make it insufficient. The statement in that form is just for trapping the over-smartness.:)

HTHs.
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m should not have been a variable here which you are missing i guess and instead focused on remainder being 4. If m's value is fixed then what you say is right. Otherwise, whenever there are variables to deal with be more cautious.
vatsal240102
I get your point about it being too direct but according to Question stem & Statement 1, theoretically shouldn't it be true that the values of p,q & m will always be such that the remainder has to be 4? How do we disprove it to eliminate A
unraveled
vatsal240102Why is statement 1 insuff. Isn't it of the form Dividend=Divisor(Quotient) + Remainder?
sset92
If p and q are positive integers such that q > p, what is the remainder when q is divided by p?

(1) q = pm + 4, where m is a positive integer.
(2) p < 4
You got it right when you say that. But don't you think that why would GMAT or any standardised test ask for a remainder by giving a simple
"Dividend=Divisor(Quotient) + Remainder" form. If it's given in such a form and asks for a simple(as it looks in the first impression) remainder, then questions must be raised.

Even after that if you don't understand then look clearly in the St. 1 and think of 4 which is remainder here as it looks like(more so when m too is an integer).

Here, there are three variables q,p and m. Assuming two would give us the third. So, with two variables(p and m) having infinite possibilities, there is high chances of getting infinite number of remainder when the third variable is divided by one of the two - in our case when q is divided by p.

But we need only two different values of remainder to make it insufficient. The statement in that form is just for trapping the over-smartness.:)

HTHs.
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