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Bunuel
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Statement 2 says In 4 hours, Deep painted twice the area as Emma did in 3 hours.So th eequation should be
2e=t-e

Krunaal
Let t be the total work i.e. work to complete the wall

Emma completed e in 3 hrs, Deep completed t-e in 4 hours, and Sam can complete t in 4.5 hours

We need to find, \((\frac{e}{3} + \frac{t-e}{4}) * k = t\) ; where k is the time taken by Emma and Deep to paint the wall working together

\(k = \frac{12t}{e+3t}\)
.................(1)

Statement 1

\((\frac{e}{3} + \frac{t-e}{4} + \frac{2t}{9})*2 = t\)
3e = t
Subs. in 1, we get k = 3.6 SUFFICIENT

Statement 2

\(\frac{2t}{9} * 4 = 2e\)
4t = 9e
Subs. in 1 also gives k SUFFICIENT

Answer D.

However, I'm skeptical because in a DS question the answers of St. 1 and 2 should match, here the value of k differs. Can someone please help me in case I went wrong somewhere above?
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Emma and Deep are painting a wall. Emma started painting the wall alone and worked for 3 hours. Then she left and Deep completed painting the rest of the wall in 4 hours. Sam alone can paint the wall in 4.5 hours completely. How long would it take to paint the wall, if Emma and Deep worked together?

Let's rate of Emma, Deep and Sam be e, d and s.
Total work = W
We are given:
3*e + 4*d = W-------(1)
4.5*s = W-------------(2)
We need to find t for t*(e+d) = W

(1) Emma, Deep, and Sam together can finish the painting of the wall in 2 hours.
Sufficient,
2*(e+d+s) = W
from (1) and (2),
we can get e+d in the form of W
and we can solve for t = W/(e+d)

(2) In 4 hours, Deep painted twice the area as Emma did in 3 hours.
Sufficient,
4*d = 2*(3*e)
from (1) and (2),
we can get e+d in the form of W
and we can solve for t = W/(e+d)

(D) is the answer.
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