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shriwasakshat
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University has published the list of subjects in two columns 01 Jun 2025, 03:01
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D
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35% (medium)

Question Stats:

74% (01:39) correct 26% (01:36) wrong based on 144 sessions

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University has published the list of subjects in two columns, Column X and Column Y. A student has to choose one subject from Column X and one from Column Y. There are 18 possible pairs of subjects possible and no other subject apart from there. If there are fewer subjects in Column X than Column Y. So, how many subjects are there in column Y?

(1) There are total 9 subjects on the two columns.

(2) There are total 3 subjects on column X.
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D
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shriwasakshat
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University has published the list of subjects in two columns 01 Jun 2025, 03:11
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If numbers of subjects in Column X=m and numbers of subjects in column Yen then, m*n = 18

So, the possible combination of (m*n = 18) are
(1,18), (2,9), (3,6), (6,3), (18,1)

Since there are fewer subjects in Column X than Column Y.

So, remove the possibility (6, 3) & (18, 1) So, possible combination are (1,18), (2,9), (3,6)

From statement (1)

There are total 9 subjects on the two column So, m + n = 9

Only possible combination is (3, 6) So, sufficient.

From statement (2)

There are 3 subjects on Column X. So, definitely (3, 6) satisfies the condition. So sufficient.

Hence option (D) is correct answer.
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University has published the list of subjects in two columns 01 Jun 2025, 10:24
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A student must choose:

1 subject from Column X

1 subject from Column Y

Total number of possible subject pairs = 18

Also: Number of subjects in Column X < Number of subjects in Column Y

Let: x = number of subjects in Column X
y = number of subjects in Column Y

Number of subject pairs=x⋅y=18

statement 1 says x+y = 9

In addition to the above we also know that there are fewer subjects in X than Y, therefore remove the possibility (6, 3) & (18, 1) (9,2)

Let's find pairs of factors of 18 that satisfies both the conditions mentioned above

the pair would be (3,6)

Statement 1 is sufficient

statement 2 x= 3
x.y=18 and x =3 therefore y =18/3 =6

statement 2 is also sufficient

hence answer is D
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University has published the list of subjects in two columns 02 Sep 2026, 09:04
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Let's solve it step by step.
Let:
  • Number of subjects in Column X = xx
  • Number of subjects in Column Y = yy
A student chooses one from X and one from Y, so the number of possible pairs is:
x×y=18x \times y = 18
And we're told:
x<yx<y
We need to find yy.
Statement (1)
Total subjects:
x+y=9x+y=9
We have:
xy=18xy=18
The factor pairs of 18 are:
  • 1×181\times18 → sum 19
  • 2×92\times9 → sum 11
  • 3×63\times6 → sum 9
Since x<yx<y, the only possibility is:
x=3,y=6x=3,\quad y=6
So Statement (1) alone is sufficient. ❌ Wait — this means the answer cannot be D.
Statement (2)
x=3x=3
Since:
xy=18xy=18 3y=183y=18 y=6y=6
So Statement (2) alone is also sufficient.
✅ Answer: D — Each statement alone is sufficient.
And the number of subjects in Column Y is:
6\boxed{6}
GMAT tip: For Data Sufficiency, you don't need to solve the question completely; you only need to determine whether each statement gives you one unique answer.
shriwasakshaLet's solve it step by step.Let:
  • Number of subjects in Column X = xx
  • Number of subjects in Column Y = yy
A student chooses one from X and one from Y, so the number of possible pairs is:
x×y=18x \times y = 18
And we're told:
x<yx<y
We need to find yy.
Statement (1)
Total subjects:
x+y=9x+y=9
We have:
xy=18xy=18
The factor pairs of 18 are:

  • 1×181\times18 → sum 19
  • 2×92\times9 → sum 11
  • 3×63\times6 → sum 9
Since x<yx<y, the only possibility is:
x=3,y=6x=3,\quad y=6
So Statement (1) alone is sufficient. ❌ Wait — this means the answer cannot be D.
Statement (2)
x=3x=3
Since:
xy=18xy=18 3y=183y=18 y=6y=6
So Statement (2) alone is also sufficient.
✅ Answer: D — Each statement alone is sufficient.
And the number of subjects in Column Y is:
6\boxed{6}
GMAT tip: For Data Sufficiency, you don't need to solve the question completely; you only need to determine whether each statement gives you one unique answer.tUniversity has published the list of subjects in two columns, Column X and Column Y. A student has to choose one subject from Column X and one from Column Y. There are 18 possible pairs of subjects possible and no other subject apart from there. If there are fewer subjects in Column X than Column Y. So, how many subjects are there in column Y?

(1) There are total 9 subjects on the two columns.

(2) There are total 3 subjects on column X.
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