Bunuel
If a coffee shop sold 600 cups of coffee, some of which were large cups and the remainder of which were small cups, what was the revenue that the coffee shop earned from the sale of coffee?
(1) The number of large cups sold was 3/5 the total number of small cups sold.
(2) The price of a small cup of coffee was $ 1.50.
Given that a coffee shop sold 600 cups of coffee, which can be sold in either Large cups or Smaller cups.
let the larger cups and small cups be L and S respectively.
so, L+S = 600.
we need to find L and S , along with their prices to calculate the revenue of coffee shop.
Statement 1:
(1) The number of large cups sold was 3/5 the total number of small cups sold.
L = (3/5)*S
Thus, L:S = 3x : 5x
8x = 600, and x = 75
Large cups = 3*75 = 225 cups
Small cups = 5*75 = 385 cups.
we know the number of cups sold individually, but we don’t know the prices for small and large cups.
Hence
insufficient.
Statement 2:
(2) The price of a small cup of coffee was $ 1.50.
Without knowing the price of the larger cup or the number of cups sold. We cannot ascertain the revenue of the coffee shop.
Hence
insufficient.
Combining both statements 1 and 2, we get
The number of large cups = 225
The number of smaller cups = 385
The price of small cup of coffee was $ 1.50.
Without knowing the price of the larger cup of coffee, we cannot find the revenue of the coffee shop.
Hence
insufficient.
Option E