Amity007
A total of 30 students are arranged in a grid for morning assembly, with 6 rows and 5 columns. Each of the 30 positions in the grid represents the height of a student. The average height (in cm) of the students in row i is Ri (1 ≤ i ≤ 6). The average height of the students in column j is Cj (1 ≤ j ≤ 5). What is the value of R6?
(1) C1 + C2 + C3 + C4 + C5 = 850
(2) R1 + R2 + R3 + R4 + R5 = 850 
Good Question!
To calculate R6 we need the total of row \(6 \).
The total age of all the \(30\) candidates can be expessed either by the columns or by the rows.
Since R1 is the average age of all the students in row \(1\).The total age of the \(5\) candidates in row \(1\) is \(5\)*R1
Total age of all \(5\) candidates in row \(2\) is \(5\)*R2 and so on..
Thus \(5R1+5R2+5R3+5R4+5R5+5R6 =\) Total age of all the candidates.
\( \hspace{8mm} \) Similarly \( 6C1+6C2+6C3+6C4+6C5 =\) Total age of all the candidates.
\( 6(C1+C2+C3+C4+C5) = 5(R1+R2+R3+R4+R5+R6) \)...(1)
(1) C1 + C2 + C3 + C4 + C5 = 850
Thus total age of the \(30\) candidate \( = 6 *850 = 5100 \)
Also R1\(+\)R2\(+\)R3\(+\)R4\(+\)R5\(+\)R6 \(=1020\)... from...(1)
Doesn't help to find R6
INSUFF.(2) R1 \(+\) R2 \(+\) R3 \(+\) R4 \(+\) R5\( = 850\)
By itself this doesn't help to find R6.
INSUFF. 1+2
R1+R2+R3+R4+R5+R6 \(= 1020\)...from ( Stmt. i)
R1+R2+R3+R4+R5 \(= 850\hspace{9mm} \)... from ( Stmt. ii)
\((i)-(ii) =\) R6 \(= 170\)
SUFF. Ans C
Hope it helped.