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28 Feb 2026, 06:33
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
38% (02:18) correct
62%
(02:17)
wrong
based on 61
sessions
History
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Time
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Not Attempted Yet
April has 30 days. During one April, a certain grocery store sold between 100 and 300 boxes of cereal each day. Did the store sell more than 6,500 boxes of cereal during that month?
(1) During the first 18 days, the store sold an average of 200 boxes per day.
(2) During the last 18 days, the store sold an average of 230 boxes per day.
(1) During the first 18 days, the store sold an average of 200 boxes per day.
(2) During the last 18 days, the store sold an average of 230 boxes per day.
06 Mar 2026, 10:59
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kevincan
(1) During the first 18 days, the store sold an average of 200 boxes per day.
So total = \(18*200 = 3600 \)
We do not know about the last \(12\) days
If \(12 *101 = 1212\) - No to the stem
If \(12*299 = 3588\) - Yes to the stem.
INSUFF.
(2) During the last 18 days, the store sold an average of 230 boxes per day.
So total \(= 18*230 = 4140\)
We do not know about the first \(12\) days
If \(12 *101 = 1212\) - No to the stem
If \(12*299 = 3588\) - Yes to the stem.
INSUFF.
1+2
\(18 +18 = 36\), So \(6\) days are being counted in both.
Let us seperate the \(6\) days and assign values, such that these six days align with all the conditions of this question.
i.e First \(18\) days total \(= 3600\) and Last \(18\) days total \(= 4140\)
Assigning minimum value to the six days \(= 101 \), so total \(= 6*101 = 606\)
First \(12\) days \(= 2994 \)
Centre \(6\) days \(= 606\)
Last \(12\) days \(= 3534 \)
Total \(2994 +606 + 3534= 7134\) -> Yes to the stem
Assigning maximum value to the six days \(= 299\), then total ->\(6*299= 1794\)
First \(12\) days = \(1806\)
Centre \(6\) days \(= 1794\)
Last \(12\) days = \(2346\)
Total \(1806 +1794 + 2346 =5946 \)-> No to the stem.
INSUFF.
Ans E
Hope it helped.
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