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kevincan please post the solution
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It’s hard for me to improve on that tall guys solution
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It’s hard for me to improve on that tall guys solution

kevincan, please check and confirm the OA. Thank you for cooperation!
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The answer is C


From statement number one, it’s tempting to conclude that C is equal to 200. however, one mustn’t assume that the difference between February and March’s earnings is equal to 3C. Why not ?

Because as that skinny guy said , those extra three sales in March could have generated c, 2c or 3c dollars in extra earnings , depending on whether Februarys sales were 8, 9 or higher . From statement number one all we can conclude is that his earnings in March were 1600 or higher .
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What I don't understand exactly is, for statement 1 case 2, m might be less than OR EQUAL TO 13.

Assuming m=13, february doesn't get a commission so for c(m-10)=600, we have c(3)=600 which implies c=200 which would contradict S2 so case 2 cannot be taken as entirely true unless we exclude m=13. So, in this situation, are we rejecting m=13 because of statement 2 (c essentially MUST be > 250 which is only true for m = 11 or 12) to get the answer C?
ThatTallGuy


I was thinking about the same:
(1) Commission is 200$,
(2) Commission is more than 250$.

They contradict each other,
Besides, there is no way of certainty about either March, February or January.

UPD: I missed one scenario:

Base = $1,000. Commission = c per subscription beyond 10. March subscriptions = m. We need March total earnings.
Statement 1 alone:
Two possible cases:
Case A (m > 13): Both months earn commission.
  • March = 1000 + c(m − 10)
  • Feb = 1000 + c(m − 13)
  • Difference = 3c = 600 → c = 200
  • But we don't know m, so March earnings = 1000 + 200(m − 10) — unknown
Case B (10 < m ≤ 13): March earns commission, Feb doesn't (m − 3 ≤ 10).
  • March = 1000 + c(m − 10)
  • Feb = 1000
  • Difference = c(m − 10) = 600
  • March = 1000 + 600 = 1600
We don't know which case, so S1 alone is not sufficient.
Statement 2 alone: January sold 18, earned > $3,000.
  • 1000 + 8c > 3000 → c > 250
  • Doesn't tell us March sales. Not sufficient.
Combined: S2 says c > 250. In Case A, c = 200 — contradicts S2. So Case A is eliminated. Must be Case B. March earnings = $1,600. Sufficient.

If I missed something, let me know.
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are we rejecting m=13 because of statement 2 (c essentially MUST be > 250 which is only true for m = 11 or 12) to get the answer C?

That’s exactly it . Remember that the statements are never contradictory, so if 2 tells you that c > 250, and you concluded from 1 that c must be 200, there’s something wrong with your reasoning ( or the question )
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Thanks for the clarification!
kevincan
are we rejecting m=13 because of statement 2 (c essentially MUST be > 250 which is only true for m = 11 or 12) to get the answer C?

That’s exactly it . Remember that the statements are never contradictory, so if 2 tells you that c > 250, and you concluded from 1 that c must be 200, there’s something wrong with your reasoning ( or the question )
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Hope you enjoyed the question. Gems like this one are not easy for me to think up
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How did you come up with " Case B (10 < m ≤ 13): March earns commission, Feb doesn't (m − 3 ≤ 10)"?

ThatTallGuy


I was thinking about the same:
(1) Commission is 200$,
(2) Commission is more than 250$.

They contradict each other,
Besides, there is no way of certainty about either March, February or January.

UPD: I missed one scenario:

Base = $1,000. Commission = c per subscription beyond 10. March subscriptions = m. We need March total earnings.
Statement 1 alone:
Two possible cases:
Case A (m > 13): Both months earn commission.
  • March = 1000 + c(m − 10)
  • Feb = 1000 + c(m − 13)
  • Difference = 3c = 600 → c = 200
  • But we don't know m, so March earnings = 1000 + 200(m − 10) — unknown
Case B (10 < m ≤ 13): March earns commission, Feb doesn't (m − 3 ≤ 10).
  • March = 1000 + c(m − 10)
  • Feb = 1000
  • Difference = c(m − 10) = 600
  • March = 1000 + 600 = 1600
We don't know which case, so S1 alone is not sufficient.
Statement 2 alone: January sold 18, earned > $3,000.
  • 1000 + 8c > 3000 → c > 250
  • Doesn't tell us March sales. Not sufficient.
Combined: S2 says c > 250. In Case A, c = 200 — contradicts S2. So Case A is eliminated. Must be Case B. March earnings = $1,600. Sufficient.

If I missed something, let me know.
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Can you solve it once for better understanding?
Bunuel


kevincan, please check and confirm the OA. Thank you for cooperation!
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Ewa earns additional earnings only from the amount of subscriptions beyond 10. This means that for March, she earned 1000 or 1000 + c(m-10) if m>10.
So, if there is a month when she did no more than 10 sales, she will earn only 1000.

Statement (1)
Let's bring down 3 different m ranges (scenarios):
Range 1: m ≤ 10
We get the same 1000$ earning both for March and February, which contradicts the statement itself.

Range 2: 10 < m ≤ 13 (Scenario B)
This means that 7 < m-3 ≤ 10. m-3 is the count of subscriptions for February. Therefore, Ewa earned 1000$ for February and 1600$ for March sales.
No matter the value of m in this range, we will have the same 600$ earnings from subscriptions.
m = 11 -> c = 600$,
m = 12 -> c = 300$,
m = 13 -> c = 200$ (this case will be later excluded).

Total earnings remain the same - 1600$

Range 3: m > 13 (Scenario A)
This means that m - 3 > 10. Therefore, Ewa sold more than 10 subscriptions in February. After simplifying the stuff we have, c = 200.

Statement (1) alone is insufficient because we do not know exactly what the earnings are, only the difference between the February and March earnings.
Statement (2) alone is insufficient as well, because it just brings the info that c > 250$.

Now, let's consider the statements together:
At first glance, if we try to solve it quickly, Statements (1) and (2) contradict each other (c = 200 and c > 250)
In fact, it just completely removes Scenario A and leaves us with two values of m: 11 and 12 from Scenario B. With both values of m, both Statements work, and in both cases, we have the same earnings - 600$ on commissions and 1600$ in total.
There are no other scenarios that can work by combining these 2 statements, and there are no other solutions to this question. We solved the problem. :)
UPD: The goal is to answer if we can give one exact solution for the problem. Combining the statements, we can surely say that Ewa's March earnings are 1600$.

Hence, the answer is C.

BadalDewani
How did you come up with " Case B (10 < m ≤ 13): March earns commission, Feb doesn't (m − 3 ≤ 10)"?


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Fantastic explanation
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Thank you for this interesting challenge as well, Kevin.

I made the same mistake, but after reviewing found out how incredible it is.
kevincan
Fantastic explanation
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percyboi66
What I don't understand exactly is, for statement 1 case 2, m might be less than OR EQUAL TO 13.

Assuming m=13, february doesn't get a commission so for c(m-10)=600, we have c(3)=600 which implies c=200 which would contradict S2 so case 2 cannot be taken as entirely true unless we exclude m=13. So, in this situation, are we rejecting m=13 because of statement 2 (c essentially MUST be > 250 which is only true for m = 11 or 12) to get the answer C?

Yes, you are correct.
Our goal is to find if it is possible to find one exact solution. And the mentioned scenario of 11 or 12 sales on March gives us the only solution without any contradiction (because the commission for each sale beyond 10 is 600$ and 300$, respectively), which is 1600$ total earnings.

The cases are mentioned in the ranges with less than or equal to 13 to visualise the edge case when February earnings do not include anything except the base salary.
The same case can later be excluded thanks to Statement (2).
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