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Alloy A is 30 percent copper by weight, and Alloy B is 12 percent copper by weight. If Alloy A and Alloy B are combined to produce an alloy that is 18 percent copper by weight, how many kilograms of Alloy B are used?
(1) To produce the final alloy, 40 kilograms of Alloy A are used.
(2) The final alloy weighs 120 kilograms.
(1) To produce the final alloy, 40 kilograms of Alloy A are used.
(2) The final alloy weighs 120 kilograms.
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M47-216
28 Jun 2026, 10:45
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GMAT Club Official Solution:
Alloy A is 30 percent copper by weight, and Alloy B is 12 percent copper by weight. If Alloy A and Alloy B are combined to produce an alloy that is 18 percent copper by weight, how many kilograms of Alloy B are used?
(1) To produce the final alloy, 40 kilograms of Alloy A are used.
Let b be the number of kilograms of Alloy B used.
Copper from Alloy A = 30% of 40 = 12 kilograms.
Copper from Alloy B = 12% of b = 0.12b.
Since the final alloy is 18% copper:
12 + 0.12b = 0.18(40 + b)
12 + 0.12b = 7.2 + 0.18b
4.8 = 0.06b
b = 80
Sufficient.
(2) The final alloy weighs 120 kilograms.
Let a be the number of kilograms of Alloy A used, and let b be the number of kilograms of Alloy B used.
Since the final alloy is 18% copper:
0.30a + 0.12b = 0.18(a + b)
0.30a + 0.12b = 0.18a + 0.18b
0.12a = 0.06b
b = 2a
So Alloy B must be twice Alloy A. Since the final alloy weighs 120 kilograms, Alloy B must be 2/3 of the final alloy, which is 2/3 * 120 = 80 kilograms.
Sufficient.
Answer: D.
Alloy A is 30 percent copper by weight, and Alloy B is 12 percent copper by weight. If Alloy A and Alloy B are combined to produce an alloy that is 18 percent copper by weight, how many kilograms of Alloy B are used?
(1) To produce the final alloy, 40 kilograms of Alloy A are used.
Let b be the number of kilograms of Alloy B used.
Copper from Alloy A = 30% of 40 = 12 kilograms.
Copper from Alloy B = 12% of b = 0.12b.
Since the final alloy is 18% copper:
12 + 0.12b = 0.18(40 + b)
12 + 0.12b = 7.2 + 0.18b
4.8 = 0.06b
b = 80
Sufficient.
(2) The final alloy weighs 120 kilograms.
Let a be the number of kilograms of Alloy A used, and let b be the number of kilograms of Alloy B used.
Since the final alloy is 18% copper:
0.30a + 0.12b = 0.18(a + b)
0.30a + 0.12b = 0.18a + 0.18b
0.12a = 0.06b
b = 2a
So Alloy B must be twice Alloy A. Since the final alloy weighs 120 kilograms, Alloy B must be 2/3 of the final alloy, which is 2/3 * 120 = 80 kilograms.
Sufficient.
Answer: D.
General Discussion
25 Jun 2026, 22:48
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A = 30% copper
B = 12% copper
final A&B = 18% copper.
say A has 100x total.
so copper is 30x
B has 100y total
so copper is 12y
mixture is = 100x+100y
copper = 30x+12y
this is 18%
30x+12y = (18/100) (100x+100y)
we get, y=2x
need to find x.
S-1
x=40
this is sufficient.
S-2
100x+100y= 120
30x+12y = (18/100)(120)
we know that y=2x
30x + 24x = 216
54x= 216
x = 4
sufficient
choice D
B = 12% copper
final A&B = 18% copper.
say A has 100x total.
so copper is 30x
B has 100y total
so copper is 12y
mixture is = 100x+100y
copper = 30x+12y
this is 18%
30x+12y = (18/100) (100x+100y)
we get, y=2x
need to find x.
S-1
x=40
this is sufficient.
S-2
100x+100y= 120
30x+12y = (18/100)(120)
we know that y=2x
30x + 24x = 216
54x= 216
x = 4
sufficient
choice D
Bunuel
25 Jun 2026, 23:16
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use alligation menthod; a: 30% b=12%
18%
18-12=6% 30-18=12%
1 : 2
1) To produce the final alloy, 40 kilograms of Alloy A are used.- if alloy a is 40 then alloy b will be 80 since in ratio 1:2, hence sufficient
2) The final alloy weighs 120 kilograms.- gives weight for both in 1:2 i.e 40 and 80 hence sufficient.
18%
18-12=6% 30-18=12%
1 : 2
1) To produce the final alloy, 40 kilograms of Alloy A are used.- if alloy a is 40 then alloy b will be 80 since in ratio 1:2, hence sufficient
2) The final alloy weighs 120 kilograms.- gives weight for both in 1:2 i.e 40 and 80 hence sufficient.
