Two uniform cleaning solutions contain only cleaning concentrate and

Question

Two uniform cleaning solutions contain only cleaning concentrate and water. In solution A, the ratio of cleaning concentrate to water is 1 to 3. In solution B, the ratio of cleaning concentrate to water is 2 to 3. If 24 liters of solution A are poured into solution B, what is the ratio of cleaning concentrate to water in the resulting solution B?

(1) After the 24 liters are added, solution B contains 18 liters more water than cleaning concentrate.
(2) Before the 24 liters are added, solution B contains 6 liters more water than cleaning concentrate.

M47-217

Bunuel · Accepted Answer

GMAT Club Official Solution:

Two uniform cleaning solutions contain only cleaning concentrate and water. In solution A, the ratio of cleaning concentrate to water is 1 to 3. In solution B, the ratio of cleaning concentrate to water is 2 to 3. If 24 liters of solution A are poured into solution B, what is the ratio of cleaning concentrate to water in the resulting solution B?

(1) After the 24 liters are added, solution B contains 18 liters more water than cleaning concentrate.

Since in solution A, the ratio of cleaning concentrate to water is 1 to 3, the 24 liters from solution A contain 6 liters of cleaning concentrate and 18 liters of water.

Let the amounts of cleaning concentrate and water in solution B be 2x and 3x.

After the addition:

Cleaning concentrate = 2x + 6
Water = 3x + 18

So:

(3x + 18) - (2x + 6) = 18

x + 12 = 18

x = 6

Thus, after the addition, solution B contains 18 liters of cleaning concentrate and 36 liters of water. Therefore, the ratio of cleaning concentrate to water is:

18 : 36 = 1 : 2

Sufficient.

(2) Before the 24 liters are added, solution B contains 6 liters more water than cleaning concentrate.

Since solution B has cleaning concentrate and water in the ratio 2 to 3, solution B contains 12 liters of cleaning concentrate and 18 liters of water.

The 24 liters from solution A contain 6 liters of cleaning concentrate and 18 liters of water. So after the addition, solution B contains:

12 + 6 = 18 liters of cleaning concentrate

and

18 + 18 = 36 liters of water.

Therefore, the ratio of cleaning concentrate to water is:

18 : 36 = 1 : 2

Sufficient.

Answer: D.

paragw · Answer

Solution A (24 liters total):
Ratio is 1:3, which means 6 liters of concentrate and 18 liters of water.

Initial Solution B:
Ratio is 2:3. Let concentrate = 2x and water = 3x.

Statement 1:
Final water minus final concentrate equals 18.
(3x + 18) - (2x + 6) = 18
x + 12 = 18 -> x = 6. (Sufficient)

Statement 2:
Initial water minus initial concentrate equals 6.
3x - 2x = 6 -> x = 6. (Sufficient)

Hence,  D

vasu1104 · Answer

solution A
cleaning concentration : water = 1:3
total volume =24 litre

so 4x =24
x=6

so cleaning concentration= 6, water= 18

now solution B 
cleaning concentration : water = 2:3

s-A added to B.
cleaning concentration = 6+2p
water= 18+3p

find = 6+2p/18+3p. 
find p to get the ration.

S-1
18+3p = 18 + 6+2p
p= 6

sufficient.

S-2
3p = 6+2p
p=6

sufficient.

choice D

HarishChaitanya · Answer

Let solution B initially have concentrate : water = 2k:3k.
Solution A has ratio 1:3and total volume 24L.
=>Total parts = 1+3=4⇒each part = 6L 
So, in solution A: concentrate = 6L, water = 18L.
After mixing into B:
Concentrate = 2k+6
Water = 3k+18

Using statement (1): Water is 18 L more than concentrate after mixing
(3k+18)−(2k+6)=18⇒k+12=18⇒k=6

Using statement (2): Before mixing, water is 6 L more than concentrate
3k−2k=6⇒k=6

Now substitute k=6: 
Final ratio = (2k+6):(3k+18)=(12+6):(18+18)=18:36=1:2.
Thus, both statements independently give the same result.
Final answer: Ratio = 1:2 and option (D) — each statement alone is sufficient.

Edskore · Answer

The key move here is setting up Solution B's initial volume correctly before evaluating either statement. Let me walk through it.

Setup: Solution A has ratio 1:3 (concentrate:water) with 24 total liters. So A contains 6L concentrate and 18L water. Solution B has ratio 2:3. Let concentrate in B = 2k, water in B = 3k.

After pouring A into B:
- Concentrate = 2k + 6
- Water = 3k + 18

We need to find k to get the ratio.

1) "After adding, solution B contains 18 liters more water than concentrate"
(3k + 18) - (2k + 6) = 18
k + 12 = 18
k = 6

That pins it down completely. Concentrate = 18, Water = 36. Ratio = 1:2. Sufficient.

2) "Before adding, solution B contains 6 liters more water than concentrate"
3k - 2k = 6
k = 6

Same value of k, different route. Sufficient.

Answer is D.

The trap most people fall into: they see both statements and assume you need both together to figure out the ratio before vs. after mixing. The reason it's D and not C is that each statement independently locks down k - you get the full picture from either one alone. Statement 2 is actually the cleaner version because it doesn't require you to track the post-mixing composition at all.

SS990 · Answer

Given: Below

C 
 W 
 Total 
 
  A 
 1/4 
 3/4 
 24L 
 
  B 
 2/5 
 3/5 
 B 
 
  Resultant 
 Cr 
 Wr

To find: Cr:Wr

(1)  3x24/4=(3B/5)+18  so this is sufficient to know Cr:Wr
(2) 3B/5 = 2B/5+6 thsi is sufficient to know B hence Cr:Wr

Hence answer is D

Two uniform cleaning solutions contain only cleaning concentrate and

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