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Updated on: 13 Aug 2020, 21:52
Originally posted by ShailendraSYadav on 13 Aug 2020, 12:37.
Last edited by ShailendraSYadav on 13 Aug 2020, 21:52, edited 1 time in total.
Last edited by ShailendraSYadav on 13 Aug 2020, 21:52, edited 1 time in total.
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Dear CV team,
Can you please help me with the approach--
How many even numbers between 199–401 can be given by below formula—
=> {(last number divisible by 2) - (1st number divisible by 2)}/ 2 + 1
=> (400-200)/2 +1 = 101
and also by a + (n-1)d= last term divisible by 2
where a is the 1st term divisible by 2, n is the number of terms, d is the common difference
=> 200+ (n-1)*2=400
=> n-1= 100
=> n=101
Actual Question:- Now, If the question is how many Even numbers are there from 199–401?
do we need to calculate like, take the end values and proceed as below---
=> (401-199)/2 +1
=> 102
or
we need to calculate as below-
=> a= 1st term divisible by 2. i.e. again 200 (as 199 is not the 1st term which is divisible by 2)
=> nth term divisible by 2 i.e. again 400 (as 401 is not the nth term which is divisible by 2)
=> (400-200)/2 +1 = 101 (Again same answer as in the case of between 199-401)
Can you please help me with the approach--
How many even numbers between 199–401 can be given by below formula—
=> {(last number divisible by 2) - (1st number divisible by 2)}/ 2 + 1
=> (400-200)/2 +1 = 101
and also by a + (n-1)d= last term divisible by 2
where a is the 1st term divisible by 2, n is the number of terms, d is the common difference
=> 200+ (n-1)*2=400
=> n-1= 100
=> n=101
Actual Question:- Now, If the question is how many Even numbers are there from 199–401?
do we need to calculate like, take the end values and proceed as below---
=> (401-199)/2 +1
=> 102
or
we need to calculate as below-
=> a= 1st term divisible by 2. i.e. again 200 (as 199 is not the 1st term which is divisible by 2)
=> nth term divisible by 2 i.e. again 400 (as 401 is not the nth term which is divisible by 2)
=> (400-200)/2 +1 = 101 (Again same answer as in the case of between 199-401)
13 Aug 2020, 21:09
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ShailendraSYadav
Hello Shailendra, Thank you for writing to us.
Since we have to find the number of even numbers from 199 - 401 (from indicates both inclusive), you are counting the multiples of 2. The better approach would be to use the first one, which effectively is
[(Largest Value - Smallest Value) / Divisor] + 1 [/m], where The divisor is the number whose multiples we need.
Here the smallest value divisible by 2 is 200 and the Largest value is 400
Therefore the number of multiples = [(400 - 200)/2] + 1 = 100 + 1 = 101
Hope this helps
