Official Solution: If, in triangle \(ABC\), angle \(ABC\) is the largest and point \(D\) lies on segment \(AC\), is the area of triangle \(ABD\) larger than that of triangle \(DBC\)? Consider the diagram below:
Notice that \(BE\) is the height of triangle \(ABC\). Now, the area of triangle \(ABD\) is \(\frac{1}{2}*height*base = \frac{1}{2}*BE*AD\), and the area of triangle \(DBC\) is \(\frac{1}{2}*height*base=\frac{1}{2}*BE*DC\). So, we can see that the area of triangle \(ABD\) will be greater than the area of triangle \(DBC\) if \(AD\) is greater than \(DC\).
(1) \(AD \lt DC\). Sufficient.
(2) \(AB \lt BC\). Not sufficient.
Answer: A