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stolyar
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Find integer S. (1) S!=S (2) S!=1 22 May 2003, 01:24
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Find integer S.

(1) S!=S
(2) S!=1



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brstorewala
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Find integer S. (1) S!=S (2) S!=1 22 May 2003, 01:30
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C? :shot

:drinking

:shocked ....very good questions.......great...... :knight
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stolyar
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Find integer S. (1) S!=S (2) S!=1 22 May 2003, 01:41
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Your perfectionism scares me. C is correct.
I feel I have to create something more difficult.
As far as I remember, you have done no mistake while dealing with my problems. It is the all-time record.

I do mistakes while dealing with yours. :crying
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numlock31
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Find integer S. (1) S!=S (2) S!=1 02 Jun 2003, 11:19
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Can someone explain this to me?
If s!=1, doesnt s=1?

Thus answer is B?
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skoper
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Find integer S. (1) S!=S (2) S!=1 02 Jun 2003, 16:07
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from 1) answers are 1 and 2

from 2) answers are 0 and 1

don't forget 0! also equals 1

therefore both are needed, therefore C
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rlevochkin
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Find integer S. (1) S!=S (2) S!=1 16 Dec 2005, 22:10
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I got your trick, Stolyar

1. Insufficient.

2. 0!=1, so S=1

B stands
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rlevochkin
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Find integer S. (1) S!=S (2) S!=1 16 Dec 2005, 22:13
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I got you, stupid mistakes. To be honest, they're killing me the most.

(1) 0!=1 and 1!=1 So S=1 or S=0

(1) and (2) S=1

C.
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nakib77
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Find integer S. (1) S!=S (2) S!=1 17 Dec 2005, 02:45
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is S! = S it got to be 1

because 1! = 1 and 0! =1

now it is not zero because 0! is not equal to zero.

on the other hand statement 2) says S! = 1, so s can be 0 or 1, so it is insufficient.

my answer is A.
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automan
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Find integer S. (1) S!=S (2) S!=1 17 Dec 2005, 04:15
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numlock31
Can someone explain this to me?
If s!=1, doesnt s=1?

Thus answer is B?
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0!=1 and 1!=1

C is the answer.

From (1) we know that S=1 or S=2; From (2) we know that S=0 or S=1; From (1) and (2) we know that S=1.
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yb
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Find integer S. (1) S!=S (2) S!=1 19 Dec 2005, 18:05
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nakib77
is S! = S it got to be 1

because 1! = 1 and 0! =1

now it is not zero because 0! is not equal to zero.

on the other hand statement 2) says S! = 1, so s can be 0 or 1, so it is insufficient.

my answer is A.
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I think you are forgetting that 2! = 2, which gives 2 values for st 1)
st 2) gives 0 or 1..

together, only 1 is common, hence C.



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