tomcal36dc
Question:
If p < q and p < r, is pqr < p?
(1) pq < 0
(2) pr < 0
analyze question:
is pqr-p < 0?
p(qr-1) < 0?
find the sign of p and (qr-1). if they are opposite, it is (-), or less than 0
(1) pq < 0, so they must be opposite signs
since p < q, p must be negative and q is positive.
no information about r, so we don't know the expression (qr-1), thus Insufficient
(2) pr < 0, so they must be opposite signs
since p < r, p must be negative and q is positive.
no information about q, so we don't know the expression (qr-1), thus Insufficient
(T) Looking back (I'm trying to remember exactly what I did with the statements together. I think I just tried to think about what it would be, but I don't remember plugging in any concrete examples...I know my final answer was C, so I think I just tried to rationalize it and after thinking about it for a few moments figured it should be sufficient together...I'm guessing I let the stress of the test get to me and didn't go through it logicially
[sitting here analyzing it with more time, I see:
basically I need pq-1>0 or pq > 1.
p and q are both positive, but they could be less than 1 or greater than one creating an answer of YES or NO, thus insufficient
answer is E]
This is a difficult question: 650-700 level.
Your approach is perfect; I think the only reason that you didn't answer correctly was the panicky state. Also, trust what you think while solving a question. You can question yourself whether what you are thinking is fully correct; if you doubt yourself too much, it's going to make your jittery and can potentially make you choose a wrong answer. So, just trust your approach.
Moreover, I believe you are in-line with approaching DS questions. These few errors can be handled with enough practice. You would know the patterns to solve a specific question as soon as you see it if you practiced enough questions before.
This question is unique in its own sense.
I see that there are certain typos in your explanation. Where p should be -ve, you have written p is +ve. Guess those are just typos.
Here's how I would approach this, and I must tell you that my approach is exactly 99% same as yours;
If p < q and p < r, is pqr < p?
(1) pq < 0
(2) pr < 0
Rephrase:
pqr-p<0
p(qr-1)<0
p & (qr-1) should have opposite signs.
(1) pq<0
p AND q have opposite signs.
p<q
Thus,
p=-ve
q=+ve
Now, at this point, rather than saying that r is not known and it's insufficient. I would still validate my expression quickly. Perhaps there is no necessity, but it makes me more aware of the third variable r existence.
rephrased expression:
(-ve)*[r*(+ve)-1]
p=-1
q=1
PIN;
r=1000000000000000000000(some big number)
[r*(+ve)-1]-> +ve
+ve*-ve=-ve
r=0.000000000000000000000000000001
-ve*-ve=+ve
Note: Please do these PIN in your head. You may think that combining PIN with algebra may be unnecessary and time consuming but in my opinion it definitely increases one's chances to answer correctly.
(2)
pr < 0
And we know that p<r
p=-ve
r=+ve
p=-1
r=1
p(qr-1)
q=10
-1*(1*10-1)=-ve
q=-0.5
-1*(-)=-ve
Not Sufficient.
We know;
p=-ve
q=+ve
r=+ve
p(qr-1)
q and r are both positives, but it may be less than 1 or more than 1.
q=0.00001; r=0.000001; qr<1
q=10;r=10; qr>1
Thus,
p(qr-1) may be >0 or <0.
Not Sufficient.
If you take 1:50 minutes to solve this question, it doesn't matter. Just solve it correctly.
Correctness > Speed
Because, you will get 7-8 questions where you will save the time. So, just don't panic.
Time spend in guessing on a difficult questions that you know you can't solve. max 30 secs.
Time spend in guessing a relatively difficult question that you know you can solve given 3 minutes. go ahead and solve it.
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Another tip for PIN;
Plugging in number is great to prove an expression insufficient. 100% But, it is not so good to prove sufficiency.
Algebra; if executed completely will give a definite answer, yet it is advisable to testify your results with PIN.
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