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revital
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Find the area of the triangle whose vertices are (-6, -2), 28 Nov 2004, 07:08
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Find the area of the triangle whose vertices are (-6, -2), (-4, -6), (-2, 5).

(1) 36 (2) 18
(3) 15 (4) 30










#3



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MA
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Find the area of the triangle whose vertices are (-6, -2), 28 Nov 2004, 14:17
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the answer is 3 i.e. 15 sq unit.

draw the graph and develop triangles and rectangles and add and substract the areas of triangles and rectangles.
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vprabhala
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Find the area of the triangle whose vertices are (-6, -2), 29 Nov 2004, 10:28
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easy way of solving is using the formula

1/2 * matrix | X1-X2 Y1-Y2 |
| X2-X3 Y2-Y3 |

substitute values

1/2 * | -2 4 |
| -2 -11|


1/2(22+8)= 15 sq units.
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gmat1obsessed
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Find the area of the triangle whose vertices are (-6, -2), 29 Nov 2004, 16:00
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vprabhala,

here is a dumb question though....in matrix how we calculate the value

= (left upper * right down) - (right upper * left down)

by the way........nice formula.....was wondering how to solve this..
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vprabhala
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Find the area of the triangle whose vertices are (-6, -2), 30 Nov 2004, 10:47
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for a matrix x1 y1
x2 y2

the answer is x1*y2- y1*x2 (yeah the one u mentioned)



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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