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30 Dec 2004, 01:11
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How many ways can a committe of three be made from a pool of 5 male candidates and 3 female candidates if there is to be at least 1 male?
please show work
please show work
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30 Dec 2004, 08:43
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MMMMM
FFF
with each committe having at least 1 male
MMM
MFM
MFF
I will say 3. This sound too simple to be true. I bet there is a trick behind this.
Anticipates OA
FFF
with each committe having at least 1 male
MMM
MFM
MFF
I will say 3. This sound too simple to be true. I bet there is a trick behind this.
Anticipates OA 30 Dec 2004, 11:32
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I would say 55
Total possible committees: 8*7*6/(2*3)=56
Number of committees with no males: 1
Total committees= 56-1=55
Total possible committees: 8*7*6/(2*3)=56
Number of committees with no males: 1
Total committees= 56-1=55
