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Cosmas
Joined: 10 Apr 2012
Last visit: 20 Sep 2016
Posts: 31
Own Kudos:
Given Kudos: 13
Concentration: Finance
Schools: Goizueta '19 (I)
WE:Analyst (Commercial Banking)
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07 Jun 2012, 01:29
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Can someone please help factorize x^3 + 2x^2 = 3x.
Is it not (x+3)(x+1)(x-1)
I don't seem to get why its x(x + 3)(x – 1)
Is it not (x+3)(x+1)(x-1)
I don't seem to get why its x(x + 3)(x – 1)
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07 Jun 2012, 01:35
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x^3 + 2x^2 = 3x
x^3 + 2x^2 - 3x = 0
x ( x^2 + 2x -3 ) = 0
x ( x^2 + 3x - x - 3 ) = 0
x [ x(x+3) - 1(x+3) ] = 0
x(x+3)(x-1) = 0
x^3 + 2x^2 - 3x = 0
x ( x^2 + 2x -3 ) = 0
x ( x^2 + 3x - x - 3 ) = 0
x [ x(x+3) - 1(x+3) ] = 0
x(x+3)(x-1) = 0
07 Jun 2012, 21:49
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Cosmas
Do it step by step
x^3 + 2x^2 = 3x
transfer 3x to the other side we have
x^3 + 2x^2 - 3x = 0
we have a common factor of x among the three, as such we have
x (x^2 + 2x - 3) = 0
Now we can still factor x + 2x - 3 into
(x + 3) (x - 1)
if you are having a hard time to believe me, let's use FOIL:
x*x + 3x - 3 - 1*x = x^2 + 2x - 3
Got it?
That's why we have:
x (x + 3) (x - 1)
