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This is a general query --- if for a total distance d a person walks the first 10 miles with a speed of x mph and the rest of the distance with a speed of 2x mph....
We calculate. ---> average speed = d/(10/x+(d-10)/2x) or = total distance / total time taken .
Now the question is wether we can calculate total time by ------>
Time taken to complete whole journey = d/(x+2x) or = total distance / summation of individual speeds..
Pl. comment on this formulas validity and wether it can be used as a standard result.
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This is a general query --- if for a total distance d a person walks the first 10 miles with a speed of x mph and the rest of the distance with a speed of 2x mph....
We calculate. ---> average speed = d/(10/x+(d-10)/2x) or = total distance / total time taken .
Now the question is wether we can calculate total time by ------>
Time taken to complete whole journey = d/(x+2x) or = total distance / summation of individual speeds..
Pl. comment on this formulas validity and wether it can be used as a standard result.
Show more
First of all, what is average of two or more quantities? It is that quantity which can replace both (or more) the quantities and still retain the same sum. i.e. if we have 3 numbers given as 3, 4 and 5, their average is 4 since we can 'replace' every number by 4 and still have the same sum.
So, average speed is the speed which is kind of the 'effective' speed i.e. overall, if the vehicle maintained the same speed throughout, what would it be? Therefore, we say Average Speed = Total Distance/ Total Time
So when you want to calculate total time taken, what will you do? It will be Total Distance/Average Speed.
Therefore, Time taken to complete whole journey = d/Average Speed calculated above
There is no place for summation of individual speeds. Only in case the time for which the vehicle traveled at each speed is equal, then avg speed = sum of the two speeds/2
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.