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555-605 (Medium)|   Geometry|      
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Bunuel
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A frame 2 inches wide is placed around a rectangular picture with dime 27 Dec 2015, 10:46
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Question Stats:

74% (01:26) correct 26% (01:18) wrong based on 231 sessions

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A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?

A. 44
B. 96
C. 128
D. 144
E. 168
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B
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A frame 2 inches wide is placed around a rectangular picture with dime 27 Dec 2015, 21:50
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A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?

(12*16)-(8*12)
=96

B. 96
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A frame 2 inches wide is placed around a rectangular picture with dime 19 Jan 2016, 02:40
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Hi Peachfuzz,

I am still not sure why the answer would be 96. We have the dimensions of the picture so the area is 96 for the picture itself (8x12)

The frame is 2 inches wider so wouldnt the dimensions go up to 14 and 10? Making the total area 140

140-96 = 44.

I dont understand why this is wrong. Could you please shed some light on this!

Thanks A lot!
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A frame 2 inches wide is placed around a rectangular picture with dime 22 Jan 2016, 20:38
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Hi All,

This question is an example of a 'punch out' question - we have to find the area of EVERYTHING, then 'punch out' the part that we don't want.

We're told that a frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. We're asked for the area of the frame, in square inches.

Area of a rectangle = (length)(width)

So the area of the PICTURE is... (8)(12) = 96

The frame 'adds' 2 inches to the top, bottom, left and right 'sides' of the picture, so the area of EVERYTHING is...

(8+2+2)(12+2+2) = (12)(16) = 196

When we 'punch out' the area of the picture, we'll be left with the area of the FRAME:

192 - 96 = 96

Final Answer:
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B

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A frame 2 inches wide is placed around a rectangular picture with dime 26 Apr 2016, 03:51
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area of rectangular picture = 12 *8 = 96 sq inches
length of picture with frame = 12 + 4 = 16 inches
width of picture with frame = 8 +4 = 12 inches
area of whole picture with frame = 16 * 12 = 192 sq inches
area of frame = area of whole picture with frame - area of rectangular picture =192 - 96 =96
correct answer option B
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A frame 2 inches wide is placed around a rectangular picture with dime Updated on: 12 Jan 2019, 04:05
Originally posted by Archit3110 on 11 Jan 2019, 04:38.
Last edited by Archit3110 on 12 Jan 2019, 04:05, edited 1 time in total.
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Bunuel
A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?

A. 44
B. 96
C. 128
D. 144
E. 168
Show more


total area of picture + frame = 12+2+2 * 8+2+2 = 16*12 = 192
and picture area = 12*8= 96
so area of fram = 192-96 = 96 IMO B
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A frame 2 inches wide is placed around a rectangular picture with dime 11 Jan 2019, 12:06
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Area of photo=8*12=96
Area of photo+frame= (8+2+2)*(12+2+2)=12*16=192

Hence area of frame= 192-96=96
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A frame 2 inches wide is placed around a rectangular picture with dime 11 Jan 2019, 12:15
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IMo B

96

12+2+2=16*2=32 ×2=64
8*2=16*2=32
Add 96

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A frame 2 inches wide is placed around a rectangular picture with dime 23 Mar 2022, 09:54
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