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04 Jun 2005, 16:41
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What is the farthest distance between two points of a closed cylinder with a volume of 512*pi and a surface area of 256*pi?
A) 8*sqrt(3)
B) 8*sqrt(2)
C) 16
D) 8 (2*pi+1)
E) 8*sqrt(5)
A) 8*sqrt(3)
B) 8*sqrt(2)
C) 16
D) 8 (2*pi+1)
E) 8*sqrt(5)
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04 Jun 2005, 17:07
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pi * r^2 = 512 pi
2r * pi * h + 2 * pi* r^2 = 256 PI
From the two equations...
r=8
h=8
Draw an imaginary rectangle inside the cylinder to get the farthest two points (the diagnol of the rectagle). 16x16x8
diagnol = sqr(576) = 24
which is not an answer choice.. .
2r * pi * h + 2 * pi* r^2 = 256 PI
From the two equations...
r=8
h=8
Draw an imaginary rectangle inside the cylinder to get the farthest two points (the diagnol of the rectagle). 16x16x8
diagnol = sqr(576) = 24
which is not an answer choice.. .
