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mirhaque
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What's the area of a Rhombus with sides 5sqrt2, and a angle 09 Jul 2005, 09:04
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What's the area of a Rhombus with sides 5sqrt2, and a angle 45 degree?



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What's the area of a Rhombus with sides 5sqrt2, and a angle 11 Jul 2005, 03:02
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2h^2=5^2*2 h=5 area=5*5sqrt2
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mirhaque
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What's the area of a Rhombus with sides 5sqrt2, and a angle 11 Jul 2005, 05:25
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AJB77
25 * sqrt(2)
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That's the correct answer. Can you please explain?
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AJB77
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What's the area of a Rhombus with sides 5sqrt2, and a angle 11 Jul 2005, 06:15
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mirhaque
AJB77
25 * sqrt(2)

That's the correct answer. Can you please explain?
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I cannot see any easy way to do this without using trigonometry. Area of Rhombus = 2*Area of triangle. I used the formula:

Area of a triangle = b.c.sin(A)/2 where A is the angle included between sides b and c. Here b=c=5*sqrt(2) and A=45degrees => sin(A) = 1/sqrt(2)
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What's the area of a Rhombus with sides 5sqrt2, and a angle 11 Jul 2005, 08:37
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the sides of a rhombus are equal. draw a line line from one bigger angle to the opposite base so that the line is perpendicular to the base. this smaller triangle is 1:1:sqrt2. height is 5 and the base is 5sqrt2. area of a rhombus is height * base = 5 * 5sqrt2 = 25sqrt2.
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What's the area of a Rhombus with sides 5sqrt2, and a angle 12 Jul 2005, 00:28
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christoph
the sides of a rhombus are equal. draw a line line from one bigger angle to the opposite base so that the line is perpendicular to the base. this smaller triangle is 1:1:sqrt2. height is 5 and the base is 5sqrt2. area of a rhombus is height * base = 5 * 5sqrt2 = 25sqrt2.
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Agree Chris. A rhombus is like a ||gm with area = bs X ht. the base is given as 5 root 2, therefore, from 90-45-45, the opposite is 5, therefore area is 5 root 2 X 5 = 25 root 2.
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What's the area of a Rhombus with sides 5sqrt2, and a angle 14 Jul 2005, 19:28
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gmat2me2
50...
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Oops multipled by one more sqrt(2)

It is 25*sqrt(2)



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