Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 1008:00 PM PDT
-09:00 PM PDT
Free- full-length test + 15 concept videos + 150+ short videos + study plan!
Sep 0812:30 AM EDT
-01:30 AM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Sep 1001:00 AM EDT
-02:00 AM EDT
Learn how Keshav, a Chartered Accountant, scored an impressive 705 on GMAT in just 30 days with GMATWhiz's expert guidance. In this video, he shares preparation tips and strategies that worked for him, including the mock, time management, and more.
Sep 1507:00 PM EDT
-09:00 PM EST
Elite scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thurs Sept. 15, 2026 - Nov. 15, 2027, 7:00pm-9:00pm EST
Sep 2107:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 21, 2026 - Oct. 9, 2027, 7:00pm-10:00pm EST
05 Nov 2014, 23:49
Kudos
Bookmarks
Given AP - 1,4,7,10,13,16,19,22,25,28,31,34,37,40,43,46 …
If the first number of the progression "a", the last number of the progression "k" and the common difference "d" is given then the number of items in the progression
□ Including the first and last numbers is given by n = [(a+k)/d] + 1 e.g.: n = ((1+46)/3) +1= 15+1=16
□ Including at least one of the numbers is given by n = [(a+k)/d] e.g.: n = ((1+46)/3) = 15=15
□ Excluding the first and last numbers is given by n = [(a+k)/d] - 1 e.g.: n = ((1+46)/3)−1= 14
If you notice, the fractional value is rounded off by truncating the decimal altogether. Is that how it should be done? Or should I round off to the closest integer basing on the rounding principles?
Thanks in advance for all the help!
If the first number of the progression "a", the last number of the progression "k" and the common difference "d" is given then the number of items in the progression
□ Including the first and last numbers is given by n = [(a+k)/d] + 1 e.g.: n = ((1+46)/3) +1= 15+1=16
□ Including at least one of the numbers is given by n = [(a+k)/d] e.g.: n = ((1+46)/3) = 15=15
□ Excluding the first and last numbers is given by n = [(a+k)/d] - 1 e.g.: n = ((1+46)/3)−1= 14
If you notice, the fractional value is rounded off by truncating the decimal altogether. Is that how it should be done? Or should I round off to the closest integer basing on the rounding principles?
Thanks in advance for all the help!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
06 Nov 2014, 10:41
Kudos
Bookmarks
In your expressions, it needs to be the difference between k and a, not their sum. You should not be getting any fractional values in the expressions. Also, no need to burden your brain with the additional variations, that is just too much to keep track in the exam. Just stick with the following expression for the arithmetic sequences:
# of Terms = [(Last Term - First Term)/Spacing] + 1
Here the difference between the first and last term gives us the total distance between the end points. When we divide it by the spacing it gives us the number of gaps between the terms, we add one to then give us the number of terms.
Cheers,
Dabral
# of Terms = [(Last Term - First Term)/Spacing] + 1
Here the difference between the first and last term gives us the total distance between the end points. When we divide it by the spacing it gives us the number of gaps between the terms, we add one to then give us the number of terms.
Cheers,
Dabral
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
