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sushom101
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twixt
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ywilfred
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gsr
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In 1 day, a woman can do -> 1/16*48 of the work
In 1 day, a man can do -> 1/16*24 of the work

12 men working for 14 days do, 12*14/(16*24) = 7/16 or work.

So the amount of remaining work that needs to be done by 12 men and 12 women is 1 - 7/16 = 9/16

In 1 day, a M and a W can do, (1/16*48 + 1/16*24) = 3/64 of the work.
So to complete 9/16 of the work, they will take = (64/3)*(9/16) = 12 additional days
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sushom101
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thanks guys...though i feel its time consuming...will take me easily 3 to 4 mins.
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GMATT73
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A different approach:

X= time for 1 man to do the job
Y= time for one woman to the job

48Y*16=1
16X*24=1
therefore, 48Y*16=16X*24 ---> X=2Y (Equation 1)

12X*14+(12X+12Y)T=16X*24 (Whereas T=Time to finish the job)
12X*14+(12X+12Y)T=16X*(12*2)
SAVE TIME AND DIVIDE BY 12
14X+(X+Y)T=32X
(X+Y)T=18X
T=18X/X+Y

Substitute X=2Y from Equation 1

T=36Y/3Y
T=12
12+14=26 Total Days



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