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tina
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A Vstudy problem 25 Aug 2003, 06:44
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Can anyone help me figure this problem ?

Answer is C.


Thank you.



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A Vstudy problem 25 Aug 2003, 06:49
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minimum pat: 2 ups, 3 rights... UURRR...
now, in how many ways can we arrange UURRR? 5!/(3!*2!)=10
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mciatto
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A Vstudy problem 25 Aug 2003, 06:58
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javropu
minimum pat: 2 ups, 3 rights... UURRR...
now, in how many ways can we arrange UURRR? 5!/(3!*2!)=10
Show more


I agree with your answer, but just to clarify, the route is 3 ups and two rights.

UUURR = (5!)/(3!*2!) = 10
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mandy
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A Vstudy problem 02 Jul 2005, 18:28
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mciatto
javropu
minimum pat: 2 ups, 3 rights... UURRR...
now, in how many ways can we arrange UURRR? 5!/(3!*2!)=10

I agree with your answer, but just to clarify, the route is 3 ups and two rights.

UUURR = (5!)/(3!*2!) = 10
Show more


plz can anyone tell me from what formula you got that (5!)/(3!*2!) =
and why plz show full explanation
thanks

regards mandy
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sparky
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A Vstudy problem 03 Jul 2005, 01:29
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the formula is

(total # of squares)!/((# of squares on one side)!(number of squares on the other side)!)
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mandy
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A Vstudy problem 03 Jul 2005, 14:06
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sparky
the formula is

(total # of squares)!/((# of squares on one side)!(number of squares on the other side)!)
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:) Thanks Sparky just one thing please the total number of square is 6 But the previous posts had 5
my first instinct was to think about permutations
can u tell me more about this formula

regards

mandy



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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Thank you for understanding, and happy exploring!