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If the first number of a series is 420 and every number after the first number is multiplied by a fixed constant and the third and fourth terms of this series are 105 and 52.5, respectively, then which of the following represents the sum of the first eight terms of this sequence?
A) ((420*(1/2^8)+420(1/2^0))/2)*(8)
B) 840*2^7/(1/2^1/3)
C) (8^1/3)*420*((2^7 - 1)/(2^7))/(1/2^8)
D) (7*(8^1/3)*30*(2^8 - 1)/(2^8))/(1/(8^1/3)
E) ((8^1/3)*14*30*(2^8 - 1)/(2^7))/(1/2^1/3)
You got 1.75 min! :snipersmile:
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Fresinha - remember that this is a geometric sequence and not a consecutive series. You use the average*number of terms only when finding the sum of a consecutive series. In order to find the sum of a geometric series you use the geometric formula:
a=first term in series
r=constant
n=number of terms
sum of geometric series = a(1-r^n)/(1-r)
=420(1-1/2^8)/(1-1/2) = 420(2^8-1/2^8)/(1/2) = or the answer choice which equals 840(2^8-1)/(2^8)
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