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joemama142000
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A boat with a speed of 80mph started racing at 8:00. After 20 Feb 2006, 18:13
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A boat with a speed of 80mph started racing at 8:00. After half an hour, another boat started racing in the same direction, at a speed of 1/4 more than the previous boat. At what time will the second boat overtake the first boat?



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A boat with a speed of 80mph started racing at 8:00. After 20 Feb 2006, 18:17
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joemama142000
A boat with a speed of 80mph started racing at 8:00. After half an hour, another boat started racing in the same direction, at a speed of 1/4 more than the previous boat. At what time will the second boat overtake the first boat?
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in half hour boat A has covered 40 miles

boat B has a speed 1/4 more than boat A therefore 80*1.25 = 100

difference of speed between Boat A and Boat B = 20mph
difference in distance between boat A and B = 40 miles

so two hours after boat B starts racing

I would say after 10:30
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A boat with a speed of 80mph started racing at 8:00. After 20 Feb 2006, 18:22
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u r right it will catch at 10:30 ... the second one speed is 100 and it started at 8:30 and that time A has alread covered 40 miles

so to catch 40 miles with a speed difference of 20 miles /hr it will take 2 hrs hence B will catch at 10:30 .
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A boat with a speed of 80mph started racing at 8:00. After 20 Feb 2006, 18:32
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A boat with a speed of 80mph started racing at 8:00. After half an hour, another boat started racing in the same direction, at a speed of 1/4 more than the previous boat. At what time will the second boat overtake the first boat?


T.(S2)/(s1-s2) hours to catch up to boat that started already...

0.5 * 100/ (100-80) = 2.5 hrs..

add 2.5 to 8.00 am it is at 10.30 am ..I believe..
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A boat with a speed of 80mph started racing at 8:00. After 20 Feb 2006, 20:26
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Boat A - 80 miles per hour
Boat B - 100 miles per hour

After 1/2 an hour, A would be 40 miles ahead
B close in on A at 20 miles per hour.

So it would catch up in 2 hours. Add this to the late start of 1/2 hour, B would overtake at 10:30
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A boat with a speed of 80mph started racing at 8:00. After 21 Feb 2006, 05:55
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Well, I didnt do it the simple way like you guys did by finding the difference btw, the speed and calculating it. Thnks giving me a new method, I worked out with half an hour time limit and found out ,

got 10:30
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SimaQ
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A boat with a speed of 80mph started racing at 8:00. After 21 Feb 2006, 06:02
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Boat B will catch up at 10:30, however will overtake him a bit later :)
Let's say 1s later :)
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kook44
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A boat with a speed of 80mph started racing at 8:00. After 21 Feb 2006, 08:26
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let t be the time since B started.
Boat B is traveling @ 100mph so it will have traveled 100t miles
Boat A is traveling at 80mph, so it will have traveled 80(t + .5) miles (remember that A started .5 hours earlier than B)

therefore,
100t = 80(t + .5)
100t = 80t + 40
20t = 40
t = 2

their distances will be equal 2 hours after Boat B started, which is 10:30



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