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joemama142000
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Someone can purchase n pears with $6 or one pear with $0.32. 22 Feb 2006, 03:42
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Someone can purchase n pears with $6 or one pear with $0.32. Which way is more economical?
1). n<20
2). At the price $0.32 per pear, he can buy n+4 pear with less than $7.



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Someone can purchase n pears with $6 or one pear with $0.32. 22 Feb 2006, 05:25
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1) is insufficient beacause if we chose that n=19, so 19 pears one can get for 6$ the other one for 6.08$... or of course choose n=1 the answer is obvious... insufficient..

2) Also insufficient: simply pick numbers choose n=1 ... one will buy 1 pear for 6$ the other one will buy 5 pears for 7$ or 0.7$ for one pear.... If you increase n to 12 for example, the first one will buy one pear for 2$ the second one for 2.2$.

Together still insufficient since n can be either 1 or 12 for example....

Answer E
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Someone can purchase n pears with $6 or one pear with $0.32. 03 Mar 2006, 17:34
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I think B

1) Insufficient n<20 can be 18 or 17

2) 0.32 (n+4) = 7 solving for n gives 7. Hence sufficient

Is it right or a trap answer?
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Professor
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Someone can purchase n pears with $6 or one pear with $0.32. 03 Mar 2006, 20:25
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joemama142000
Someone can purchase n pears with $6 or one pear with $0.32. Which way is more economical?
1). n<20
2). At the price $0.32 per pear, he can buy n+4 pear with less than $7.
Show more

from 1) if n<20, the price/pear is at leat $0.333 or more. so it is suff.

from 2) per peer price if we buy peers using $6= $6/n.
per peer price if we buy peers paying $0.32 = ($6/n)+($1 or less than $1/4) = less than $6/n

so buying per peer paying $0.32 is economical.

D.
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Gordon
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Someone can purchase n pears with $6 or one pear with $0.32. 04 Mar 2006, 09:17
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but professor, 6/19 gives us 0.315 which is less than 0.32. ans 0.315 will just kep increasing as n keeps decreasing from 19 to 18 etc. so 1 should be insuff. Am I missing something here. OA please.
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Someone can purchase n pears with $6 or one pear with $0.32. 04 Mar 2006, 10:20
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nshankaran
I think B

1) Insufficient n<20 can be 18 or 17

2) 0.32 (n+4) = 7 solving for n gives 7. Hence sufficient

Is it right or a trap answer?
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I think B too. If you consider the equation in 2)
0.32(n+4) < 7
0.32n < 5.72

0.32n is the cost of buying n at 0.32 which is 5.72 and < 6. So it is cheaper to buy at 0.32. So B.
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Someone can purchase n pears with $6 or one pear with $0.32. 04 Mar 2006, 11:37
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Gordon
but professor, 6/19 gives us 0.315 which is less than 0.32. ans 0.315 will just kep increasing as n keeps decreasing from 19 to 18 etc. so 1 should be insuff. Am I missing something here. OA please.
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yes, yes. thats right. it is not A. i did it the other way round.
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Someone can purchase n pears with $6 or one pear with $0.32. 05 Mar 2006, 22:03
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Option A ruled it out, as there is more than one answer possible.
For n = 19, n = 1, get different answers

Option B, n < 17,

answer is straight forward.

B



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