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I made first the mistake to simplify as follow : x^4=x^2 by dividing by x^2. Thus, I obtained x^2=1 and solutions=1, -1.
It was false because 0 belongs to the solution.
Since then, I do X^4-X^2=0 => x2(x2-1) sol=-1,0,1
---------------------------------
I've done later the same mistake.
The pb was of that kind : x/y>1.
So I multiplied by y : x*y/y>y => x>y
It was wrong again because there was one solution missing.
The right thing to do is : x/y-1>0 =>(x-y)/y >0 sol= y>0 and x>y or y<0 and x<y.
--------------------------------
So whenever I see such equations, I never divide or multiply to simplify, but put everything on one side.
Today I had an OG11 pb to solve(144)
If (4-x)/(2+x)=x , what is the value of x^2+3x-4?
I did as I learnt and put everything on one side :
(4-x)/(2+x) - x =0 etc... and was right.
As I looked the answer of OG11, I saw that they did as following:
They multiplied both sides by (2+x), yielding 4-x=x(2+x), which is quite faster.
So I'm totally blured, since I thought it was not possible to do that way!
Are there any rule for simplifying such equations?
Thanks for your answers!
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But what about my first example. There again it is not possible to cancel, though it is an egality.
Quote:
I made first the mistake to simplify as follow : x^4=x^2 by dividing by x^2. Thus, I obtained x^2=1 and solutions=1, -1. It was false because 0 belongs to the solution.
But what about my first example. There again it is not possible to cancel, though it is an egality.
Quote:
I made first the mistake to simplify as follow : x^4=x^2 by dividing by x^2. Thus, I obtained x^2=1 and solutions=1, -1. It was false because 0 belongs to the solution.
Since then, I do X^4-X^2=0 => x2(x2-1) sol=-1,0,1
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oh yes, we cannot do that in this case...all variables should be moved to one side..
if x^4=x^2, we should know that x could be -1, 0, and 1.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.