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getzgetzu
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x, y, z are numbers on the number line. Is x<y<z? 1) 27 Apr 2006, 23:41
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x, y, z are numbers on the number line. Is x<y<z?

1) |y-x| + |y-z| = |z-x|

2) x<z



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conocieur
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 00:32
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getzgetzu
x, y, z are numbers on the number line. Is x<y<z?

1) |y-x| + |y-z| = |z-x|

2) x<z
Show more



(1) remainds me of the triangle inequality
|x-y| + |y-z| >= |x-z|

so is just equal if x<y<z or x>y>z
insuff.

(2) insuff.

together works

C
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 00:34
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conocieur
getzgetzu
x, y, z are numbers on the number line. Is x<y<z?

1) |y-x| + |y-z| = |z-x|

2) x<z


(1) remainds me of the triangle inequality
|x-y| + |y-z| >= |x-z|

so is just equal if x<y<z or x>y>z
insuff.

(2) insuff.

together works

C
Show more


What happens if y=z or y=x?
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conocieur
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 00:57
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giddi77
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getzgetzu
x, y, z are numbers on the number line. Is x<y<z?

1) |y-x| + |y-z| = |z-x|

2) x<z


(1) remainds me of the triangle inequality
|x-y| + |y-z| >= |x-z|

so is just equal if x<y<z or x>y>z
insuff.

(2) insuff.

together works

C

What happens if y=z or y=x?
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yes, I didn't notice that one, mmm, should we go for E then?
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 01:44
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It works for x=y or y=z


if x=0, y=0, z=2


0 + 2 = 2


if x=0, y=2, z=2

2 + 0 = 2
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 01:46
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sm176811
It works for x=y or y=z


if x=0, y=0, z=2


0 + 2 = 2


if x=0, y=2, z=2

2 + 0 = 2
Show more



o yeah, the triangle inequality yes, but what about x<y<z

i guess that one doesn't hold
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 01:47
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conocieur
sm176811
It works for x=y or y=z


if x=0, y=0, z=2


0 + 2 = 2


if x=0, y=2, z=2

2 + 0 = 2


o yeah, the triangle inequality yes, but what about x<y<z

i guess that one doesn't hold
Show more


What do you mean.. give an example!
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 01:50
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sm176811
conocieur
sm176811
It works for x=y or y=z


if x=0, y=0, z=2


0 + 2 = 2


if x=0, y=2, z=2

2 + 0 = 2


o yeah, the triangle inequality yes, but what about x<y<z

i guess that one doesn't hold

What do you mean.. give an example!
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using your own numbers
x=0, y=2, z=2
both hold in (1) and (2)
but since y=z
then x<y<z doesn't work

also x=0 y=1 z=2
hold in (1) and (2)
then x<y<z does work

since can obtain two different answers there is no enough info
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x, y, z are numbers on the number line. Is x<y<z? 1) 28 Apr 2006, 01:56
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Ah!! Missed that :P I guess the answer is E then!



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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Thank you for understanding, and happy exploring!