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beyondinfinity
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sm176811
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willget800
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Can one of you post the question, please?
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question is...

on the graph above, when x = 1/2, y = 2; and x =1,y=1. The graph is symmetric with repsect to the vertical linke at x = 2. According to the graph, when x = 3, y = ?
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beyondinfinity
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ok we assume it to be a parabola then the eqn of graph can be taken as

Y= a x*x + b*x + c (i.e. the standard quadratic one..)

now i need to find a,b,c which is simple as

x=2 , y=0 as it appears from graph
x=1 , y=1 as given in question
x=.5 , y=2 as given in question

so from this i wud get a,b,c

now we need to find y when x=3 , put back in the equation we will get the value of y...

i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...
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ccax
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beyondinfinity
i know this is a longer method..no doubt..but why doesn't it give the same answer...can anyone please explain it...


You can't assume the graph to be a parabola because it isn't one. And
even if it were: the y-value for x= 1/2 is only given to confuse us, so
don't use a formula and take the y-value for x=1 .
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beyondinfinity
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but i think i found my mistake this curve may be a fourth degree , sixth degree or any equation with even powers of X , since that is not clear so we cannot take it to be a "quadratic" equation.



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