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10 Apr 2019, 16:17
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There are 4 red balls, numbered 1, 2, 3, 4. Similarly there are 3 numbered blue balls and 2 numbered yellow balls. In how many ways can these 9 balls be arranged in a row, if no two blue balls have to be together?
(A) 6! × 7P3 (B) 48 × 7P3 (C) 6! × 5P3 (D) 9! – 7!×3! (E) None of the above
(A) 6! × 7P3 (B) 48 × 7P3 (C) 6! × 5P3 (D) 9! – 7!×3! (E) None of the above
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10 Apr 2019, 17:14
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Hi nivikumar93,
When posting specific GMAT questions, you'll receive more of a response if you post them to their specific sub-forums. For example, the Problem Solving forum can be found here:
quantitative-7/
GMAT assassins aren't born, they're made,
Rich
When posting specific GMAT questions, you'll receive more of a response if you post them to their specific sub-forums. For example, the Problem Solving forum can be found here:
quantitative-7/
GMAT assassins aren't born, they're made,
Rich
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
