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kook44
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 06:40
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S is the product of a list of consecutive integers from 1 to 24, and 10 k is a factor of S. What greatest value of k?
A: 1
B: 2
C: 3
D: 4
E: 5



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tapan22
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 06:55
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S is the product of a list of consecutive integers from 1 to 24, and 10 k is a factor of S. What greatest value of k?
A: 1
B: 2
C: 3
D: 4
E: 5

**********************************************

Is it E)--5?

Since this is a product of consecutive integers and 10K is a factor of S so,

A: 10*1 is a factor
B: 10*2 is a factor
C: 10*3 is a factor
D: 10*4 is a factor
E: 10*5 is a factor -----> Greatest value of K is 5
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 07:42
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Argh.
I was originally puzzled by this question. It was written wrong. Should be:

S is the product of a list of consecutive integers from 1 to 24, and 10^k is a factor of S. What greatest value of k?
A: 1
B: 2
C: 3
D: 4
E: 5

got it now....
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tapan22
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 08:14
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In that case is the answer 3?

I am not sure if this is the right approach though

I broke up each of the choices or powers of 10 into the primes:

10^1 = 5*2 --->divsible since both 2 and 5 are in the series
10^2 = 5*2*2--->divisible since both 4 and 4 are in the series
10^3 = (5*2)(5*2*2)*5 = 10*20*5-->divisible since all nos are in the series.
Fails for the rest of the choices
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tapan22
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 10:14
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Professor what was the approach you took to arrive at 4? Can you pls explain?
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M8
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 10:42
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tapan22
Professor what was the approach you took to arrive at 4? Can you pls explain?
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D it is, 4.

There are just 4 10s.
2*5 = 10
10 by itself
4*15 =60 = 10*6
20 = 10 *2

No digits left that give us zero at the end.
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 10:48
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yeah D it is

because 24/5=4 -> 4 multiples of 5
and 24/2=12 -> more than 4 multiples of 5
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 10:51
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Thanks M8 and thearch very elegant and simple explanations.
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Professor
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S is the product of a list of consecutive integers from 1 to 31 May 2006, 11:17
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tapan22
Professor what was the approach you took to arrive at 4? Can you pls explain?
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there are at least four 5's and 2's. so that makes 10^4.

1. 25/5 -1 = 4 (four) 5's
2. 24/2 = 12 (twelve) 2's.

so that makes 4 (four) 10's.



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