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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
In that case is the answer 3?

I am not sure if this is the right approach though

I broke up each of the choices or powers of 10 into the primes:

10^1 = 5*2 --->divsible since both 2 and 5 are in the series
10^2 = 5*2*2--->divisible since both 4 and 4 are in the series
10^3 = (5*2)(5*2*2)*5 = 10*20*5-->divisible since all nos are in the series.
Fails for the rest of the choices
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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
Professor what was the approach you took to arrive at 4? Can you pls explain?
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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
tapan22 wrote:
Professor what was the approach you took to arrive at 4? Can you pls explain?


D it is, 4.

There are just 4 10s.
2*5 = 10
10 by itself
4*15 =60 = 10*6
20 = 10 *2

No digits left that give us zero at the end.
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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
yeah D it is

because 24/5=4 -> 4 multiples of 5
and 24/2=12 -> more than 4 multiples of 5
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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
Thanks M8 and thearch very elegant and simple explanations.
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Re: S is the product of a list of consecutive integers from 1 to [#permalink]
tapan22 wrote:
Professor what was the approach you took to arrive at 4? Can you pls explain?


there are at least four 5's and 2's. so that makes 10^4.

1. 25/5 -1 = 4 (four) 5's
2. 24/2 = 12 (twelve) 2's.

so that makes 4 (four) 10's.



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